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lorasvet [3.4K]
2 years ago
14

Hi can someone please help with this, i need the workout as well pls

Mathematics
1 answer:
lozanna [386]2 years ago
6 0

Answer:

45

Step-by-step explanation:

98+37=135

180-135=45

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Pleaseee help me which one is it????
AURORKA [14]

Answer:

it is definitely negative, i think it is -3/2

Step-by-step explanation:

is there a better picture of the graph?

5 0
3 years ago
Find the savings plan balance after 18 months with an APR of 3% and monthly payments of $200.
ArbitrLikvidat [17]

The saving plan balance is $3,677.53.

Given that,

  • The no of months is 18.
  • The annual percentage rate is 3% so the monthly rate percentage is 0.25%.
  • And, the monthly payment is $200.

Based on the above information, the following formula should be used:

FVA = PMT×  [(1+r)^n - 1] ÷ r

= $200 × [(1+ 0.0025)^18 - 1] ÷ 0.0025

= $3,677.53

Therefore we can conclude that the saving plan balance is $3,677.53.

Learn more: brainly.com/question/14191332

4 0
2 years ago
Silvia is n years old. She has a twin sister. What is the total of their ages?
natka813 [3]

Answer:  2n

Step-by-step explanation:

Silvia is n, sister is n, total is n+n=2n.

8 0
3 years ago
The product of sin 30° and sin 60° is same as the product of cos 60 degrees tan 30 degrees and cos 30 degrees tan 60 degrees .
Pani-rosa [81]
From the unit circle:
sin 30 = 1/2, cos 30 = √3 / 2, tan 30 = √3 / 3 , tan 60 = √3;
sin 30 * sin 60 = ( cos 60 * tan 30 ) * ( cos 30 * tan 60 )
Left side of an equation:
sin 30 * sin 60 = 1/2 * √3 / 2 = √3 / 4
Right side:
( cos 60 * tan 30 ) * ( cos 30 * tan 60 ) =
= ( 1/2 * √3 / 3 ) * ( √3 / 2 * √3 ) =
= √3 / 6 * 3 / 2 = √3 / 4
√3 / 4 = √3 / 4 ( correct )
3 0
3 years ago
Suppose your marketing colleague used a known population mean and standard deviation to compute the standard error as 56.8 for s
nalin [4]

Answer:

32.793

Step-by-step explanation:

Given that  your marketing colleague used a known population mean and standard deviation to compute the standard error as 56.8 for samples of a particular size

You don't know the particular sample size but your colleague told you that the sample size is greater than 60.

When n becomes 3n, we get Std error would become instead of \frac{std dev}{\sqrt{n} }

to \frac{std dev}{\sqrt{3n} }

Thus we get standard error for new sample size = old se/sqrt 3

=\frac{56.8}{\sqrt{3} } \\=32.793

5 0
3 years ago
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