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lorasvet [3.4K]
2 years ago
14

Hi can someone please help with this, i need the workout as well pls

Mathematics
1 answer:
lozanna [386]2 years ago
6 0

Answer:

45

Step-by-step explanation:

98+37=135

180-135=45

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Find the measure of angle y. Round your answer to the nearest hundredth. (please type the numerical answer only) A right triangl
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For this case we have the following trigonometric relationship:
 cos (y) = 8/13
 Clearing the value of and we have:
 y = Acos (8/13)
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 Answer:
 
the measure of angle and is:
 
y = 52.02 degrees
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Step-by-step explanation:


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3 years ago
Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.
blagie [28]
A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0

B.
3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\
x=11
3 0
2 years ago
Can someone help me
djverab [1.8K]

Step-by-step explanation:

10)

any triangle inscribed into a circle with the baseline being a diameter of the circle must be a right-angled triangle.

the arc angle of 84° means that also the angle at Q is 84°, because the arc angle is the same as the segment angle at the center of the circle (that is how arc sngles are defined).

that means the supplementary angle (together they have 180°) of Q at the inner top angle of the small left triangle is 180 - 84 = 96°.

as the legs of this small left triangle are both the radius of the circle, this triangle is an isoceles triangle (both legs are equally long, and both angles at its baseline are equally large).

remember, the sum of all angles in a triangle is always 180°.

so,

y = (180 - 96)/2 = 42°

x is a complimentary angle (together they are 90°, remember, the large triangle is inscribed and is right-angled) to the second 42° angle

x = 90 - 42 = 48°

11)

y is the supplementary angle to 126°

y = 180 - 126 = 54°

this inner segment angle is the mean value between the 2 outer angles.

54 = (57 + 2nd outer angle of y)/2

108 = 57 + 2nd outer angle of y

2nd outer angle of y = 108 - 57 = 51°

all arc angles around a circle must be 360°.

x = 360 - 57 - 104 - 51 = 148°

12)

again, all arc angles together must be 360°.

y = 360 - 148 = 212°

x is the same angle as the top angle of a triangle inscribed to the right of the chord.

and that angle is half of the opposing arc angle (148°).

it is therefore 148/2 = 74°

and so,

x = 74°

6 0
1 year ago
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