Question

Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.

Answer 1

Answer:

$6+ \sqrt{29},6-\sqrt{29}$

Step-by-step explanation:

The given quadratic equation is $x^2-12x+7=0$

The general form of quadratic equation is given by :

$ax^2+bx+c=0$

Comparing both the equations,

a = 1, b = -12 and c = 1

The solution of a quadratic equation is given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Put all the values,

$a=\dfrac{-(-12)\pm \sqrt{(-12)^2-4\times 1\times 7} }{2(1)}\\\\=\dfrac{12\pm \sqrt{116}}{2}\\\\=\dfrac{12\pm 2\sqrt{29}}{2}\\\\=6\pm \sqrt{29}$

So, the solutions of the given equation is $6+ \sqrt{29},6-\sqrt{29}$. Hence, the correct option is (d).