Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle. This can be obtained by finding each shaded area and then adding them.
<h3>Find the expression for the area of the shaded regions:</h3>
From the question we can say that the Hexagon has three shapes inside it,
Also it is given that,
An equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon.
From this we know that equilateral triangle is the smallest, then square, then regular pentagon and then a regular hexagon.
A pentagon is shown inside a regular hexagon.
- Area of first shaded region = Area of the hexagon - Area of pentagon
An equilateral triangle is shown inside a square.
- Area of second shaded region = Area of the square - Area of equilateral triangle
The expression for total shaded region would be written as,
Shaded area = Area of first shaded region + Area of second shaded region
Hence,
⇒ Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle.
Learn more about area of a shape here:
brainly.com/question/16501078
#SPJ1
Answer:
Function B has the greater rate of change
Step-by-step explanation:
Function A has a slope of 1/3
Function B has a slope of 1/2
When comparing slopes, the higher value has the greater rate of change
1/2 > 1/3
Answer:
a=1
Step-by-step explanation:
Multiply all terms by a and cancel:
6+−6a=3+−3a
−6a+6=−3a+3(Simplify both sides of the equation)
−6a+6+3a=−3a+3+3a(Add 3a to both sides)
−3a+6=3
−3a+6−6=3−6(Subtract 6 from both sides)
−3a=−3
−3a
−3
=
−3
−3
(Divide both sides by -3)
a=1
Answer:
ΔHFG≅ΔSUT
Step-by-step explanation:
You just have to match up the sides and the angle.It's easier to color code them.
For example:
Segment SU would be congruent with HF. (both would be blue, just example color)
Angle U is congruent to angle F (red)
UT congruent to FG (green)
Answer:
Step-by-step explanation:
f(x) = 4-x
g(x) = h
+k
g(f(x)) = 2-16x+26
so put f(x) in g(x)
h
+k
h((4-x)(4-x) + k
h(-8x+16)+k
if h = 2 , then
2-16x+32 + k
and we want 26 instead of 32 so subtract 6 so K = (-6)
2-16x+32 + (-6)
2-16x+32 - 6
2-16x+26
h=2
k=(-6)
