A Panuto: Mahalagang kilalanin ang sarili at alamin ang sanling kahinaan at kakayahan bago gumawa

Physics

1 answer:

Kaylis [27]3 years ago

7 0

Answer:

Ako ay isang simpleng tao hindi mapilit sa'king kagustuhan,marespeto sa kapwa,nagsasabi ng 'po' at 'opo' lalong lalo na Kung mas nakakatanda pa sa'kin yung kausap ko.Hindi porke mahirap ako ay marami ng mang-aapi o nambu_bully sa'kin ,,,pero wala akong napansing ganun kasi kapag marespeto ka ay bumabalik at bumabalik parin yun sayo yung kabutihan na ipanapakita mo sa ibang tao.Hindi ako isang tao na kung anuman ang nakikita ko sa nakakarami ay gagayahin ko,bibilhin ko,o magdedemand lang SA MGA magulang ko para mabili yung aking kagustuhan.Isang taong marunong makuntento sa anumang meron,isang taong may respeto sa kapwa,isang taong mabuti ang loob wag nyu lng unahan,isang taong hindi magastos sa mga walang kwentang bagay,masimple at palaban sa anumang hapon na hinaharap.

Explanation:

Ano yung sa inyo???

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A cyclotron is used to produce a beam of high-energy deuterons that then collide with a target to produce radioactive isotopes f

serg [7]

Answer:

19080667.0818 m/s

0.637294 m

$2.1875\times 10^{15}$

Explanation:

m = Mass of deuterons = $3.34\times 10^{-27}\ kg$

v = Velocity

K = Kinetic energy = 3.8 MeV

d = Diameter

B = Magnetic field = 1.25 T

q = Charge of electron = $1.6\times 10^{-19}\ C$

t = Time = 1 s

i = Current = 350 μA

Kinetic energy is given by

$K=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{\dfrac{2K}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 3.8\times 10^6\times 1.6\times 10^{-19}}{3.34\times 10^{-27}}}\\\Rightarrow v=19080667.0818\ m/s$

The speed of the deuterons when they exit is 19080667.0818 m/s

In this system the centripetal and magnetic force will balance each other

$\dfrac{mv^2}{r}=qvB\\\Rightarrow \dfrac{mv^2}{\dfrac{d}{2}}=qvB\\\Rightarrow d=\dfrac{2mv}{qB}\\\Rightarrow d=\dfrac{2\times 3.34\times 10^{-27}\times 19080667.0818}{1.6\times 10^{-19}\times 1.25}\\\Rightarrow d=0.637294\ m$

The diameter is 0.637294 m

Current is given by

$i=\dfrac{nq}{t}\\\Rightarrow n=\dfrac{it}{q}\\\Rightarrow n=\dfrac{350\times 10^{-6}\times 1}{1.6\times 10^{-19}}\\\Rightarrow n=2.1875\times 10^{15}$