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LuckyWell [14K]

3 years ago

9

The answer to this question please!

2 answers:

Nikitich [7]3 years ago

5 0

What’s the question?

soldi70 [24.7K]3 years ago

4 0

can i please see the question?

you can attach it by the paperclip

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A cat rides a merry-go-round while turning with uniform circular motion. At time t1 = 2.00 s, the cat's velocity is v with arrow

goldenfox [79]

Answer:

Part a)

$a_c = 2.07 m/s^2$

Part b)

$a_{avg} = 1.32 m/s^2$

Explanation:

As we know that it makes half revolution in given time interval

so we have

$\frac{T}{2} = t_2 - t_1$

$\frac{T}{2} = 9 - 2$

$T = 14 s$

now the angular speed is given as

$\omega = \frac{2\pi}{T}$

$\omega = \frac{2\pi}{14}$

$\omega = 0.448 rad/s$

now linear speed is given as

$v = \sqrt{2.30^2 + 4.00^2}$

$v = 4.61 m/s$

now we have

$v = R \omega$

$4.61 = R(0.448)$

$R = 10.3 m$

Now centripetal acceleration is given as

$a_c = \omega^2 R$

$a_c = 0.448^2 \times 10.3$

$a_c = 2.07 m/s^2$

Part b)

Average acceleration of the cat is given as

$a_{avg} = \frac{v_2 - v_1}{\Delta t}$

$a_{avg} = \frac{2v}{\Delta t}$

$a_{avg} = \frac{2(4.61)}{9 - 2}$

$a_{avg} = 1.32 m/s^2$

7 0

4 years ago

If you have 240.0 mL of water at 25.00 °C and add 100.0 mL of water at 95.00 °C, what is the final temperature of the mixture? U

Rus_ich [418]

<u>Answer:</u> The final temperature of the mixture is 45.6°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

<u>When volume is 240.0 mL</u>

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{240.0mL}\\\\\text{Mass of water}=(1g/mL\times 240.0mL)=240g$

<u>When volume is 100.0 mL</u>

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{100.0mL}\\\\\text{Mass of water}=(1g/mL\times 100.0mL)=100g$

When two water solutions at different temperature are mixed, the amount of heat released by water present at higher temperature will be equal to the amount of heat absorbed by water present at lower temperature..

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of water solution 1 = 240 g

$m_2$ = mass of water solution 2 = 100 g

$T_{final}$ = final temperature = ?°C

$T_1$ = initial temperature of water solution 1 = 25°C

$T_2$ = initial temperature of water solution 2 = 95°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

$240\times 4.186\times (T_{final}-25)=-[100\times 4.186\times (T_{final}-95)]\\\\T_{final}=45.6^oC$

Hence, the final temperature of the mixture is 45.6°C

7 0

3 years ago

Read 2 more answers

An unbalanced force can cause an object to:

Lilit [14]

It'll speed up in the direction it's being pushed unbalanced. Or, it could slow down if applied the right amount of unbalanced power. And finally if the unbalanced push is pushed it could change the direction of it's current motion it was traveling.<span>
</span>

3 0

3 years ago

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A train is traveling at a speed of 50km/hr. How.many hours will it take the train to travel 800 km?

bagirrra123 [75]

Answer:

It would take 16 hours

Explanation:

800 divided by 50 = 16

Brainly pls

8 0

3 years ago

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A long, thin rod parallel to the y-axis is located at x = -1.0 cm and carries a uniform linear charge density of +1.0 nC/m. A se

Bad White [126]

Answer:

Hhere is the other part of the question ; What is the net electric field due to these rods at the origin? (epsilon not = 8.85*10^-12)

net electric field = 3600N/C

Explanation:

The detailed calculation is as shwon below

8 0

3 years ago