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Alex777 [14]
3 years ago
8

A man consumes 2055 kcal of food in one day, converting most of it to body temperature. If he loses half this energy by evaporat

ing water (through breathing and sweating), how many kilograms of water evaporate?
Physics
2 answers:
vitfil [10]3 years ago
8 0

Answer:

1.903 kg.

Explanation:

Energy obtained from the food, Q= 2055kCal

Half of the energy lost to evaporating water = 2055/2

= 1027.5 kCal

Latent heat of water, L = 540 kCal/kg

Q= m × L

m = 1027.5/540

= 1.903 kg.

9966 [12]3 years ago
3 0

Answer:

3.81kg

Explanation:

Given that heat lost by man Q= 2055kCal

Latent heat of water L = 540KCal/Kg

Mass of water evaporated = M

Using

Q= ML

2055= M * 540

M= 2055/540

M= 3.81kg

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The temperature of an object increases when the molecules that make up that object move faster. Thermal energy is energy possessed by an object or system due to the movement of particles within the object or the system.

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Why cable color codes are important ? what if we use three phase cables without color
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A rabbit runs 4.4 m across a lawn, stops, then runs 2.2 m back in the opposite direction. What is the rabbit’s displacement from
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3 years ago
A 1300-kg car initially has a velocity of 22.2 m/s due south. It brakes to a stop over a 180 m distance.
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The acceleration of the object which moves from an initial step to a full halt given the distance traveled can be calculated through the equation,
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Read 2 more answers
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