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777dan777 [17]
3 years ago
9

Does the banana hit the monkey if you aim straight at it?

Physics
1 answer:
tester [92]3 years ago
3 0

Answer:

Yes, because a banana is not like a boomerang. It will go straight if you aim straight.

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Oxygen-18 has an atomic number of 8. How many neutrons are in this isotope?
Alenkasestr [34]
10 is the answer (i think)
8 0
4 years ago
Read 2 more answers
A 10 kg frictionless cart is pushed at a constant force of 5.0 N for a distance of 10 m. The work done on the cart is 50J.
kykrilka [37]

1) Final kinetic energy of the cart: B) 50 J

2) Final speed of the cart: C) 3.2 m/s

3) Height reached along the ramp: A) 0.5 m

Explanation:

1)

We can solve this part of the problem by using the work-energy theorem, which states that the work done on an object is equal to the kinetic energy gained by the object itself. Mathematically:

W=K_f - K_i

where

W is the work done

K_f is the final kinetic energy

K_i is the initial kinetic energy

In this problem, the work done on the cart is

W = 50 J

And assuming it starts from rest, its initial kinetic energy is zero:

K_i = 0

Therefore, the final kinetic energy is:

K_f = K_i + W=0+50=50 J

2)

The kinetic energy of an object is the energy possessed by an object due to its motion; it is calculated as

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the cart in this problem, we have:

K = 50 J is its final kinetic energy

m = 10 kg is the cart

Therefore, solving the formula for v, we find its speed:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(50)}{10}}=3.2 m/s

3)

We can think this problem in terms of conservation of energy. In fact, as the cart rolls up the ramp, its kinetic energy is converted into gravitational potential energy, which is given by

PE=mgh

where

m is the mass

g=9.8 m/s^2 is the acceleration of gravity

h is the heigth of the cart

When the cart reaches the maximum height, all the kinetic energy has been converted into potential energy, so we can write:

K=PE\\\frac{1}{2}mv^2=mgh

Re-arranging,

h=\frac{v^2}{2g}

And since we know the initial speed of the cart along the ramp,

v = 3.2 m/s

we can find the maximum height reached along the ramp:

h=\frac{3.2^2}{2(9.8)}=0.5 m

Learn more about work, kinetic energy and potential energy:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

7 0
3 years ago
Can you please help me figure out the work for the missing quantities?
marysya [2.9K]

Answer: set up proportions

Explanation:

8 0
3 years ago
A bird is flying in a room with a velocity field of . Calculate the temperature change that the bird feels after 9 seconds of fl
Korvikt [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The temperature change is \frac{dT}{dt} = 1.016 ^oC/m

Explanation:

From the question we are told that

   The velocity field with which the bird is flying is  \vec V =  (u, v, w)= 0.6x + 0.2t - 1.4 \ m/s

   The temperature of the room is  T(x, y, u) =  400 -0.4y -0.6z-0.2(5 - x)^2 \  ^o C

    The time considered is  t =  10 \  seconds

    The  distance that the bird flew is  x  =  1 m

 Given that the bird is inside the room then the temperature of the room is equal to the temperature of the bird

Generally the change in the bird temperature with time is mathematically represented as

      \frac{dT}{dt} = -0.4 \frac{dy}{dt} -0.6\frac{dz}{dt} -0.2[2 *  (5-x)] [-\frac{dx}{dt} ]

Here the negative sign in \frac{dx}{dt} is because of the negative sign that is attached to x in the equation

 So

       \frac{dT}{dt} = -0.4v_y  -0.6v_z -0.2[2 *  (5-x)][ -v_x]

From the given equation of velocity field

    v_x  =  0.6x

    v_y  =  0.2t

     v_z  =  -1.4

So

\frac{dT}{dt} = -0.4[0.2t]  -0.6[-1.4] -0.2[2 *  (5-x)][ -[0.6x]]    

substituting the given values of x and t

\frac{dT}{dt} = -0.4[0.2(10)]  -0.6[-1.4] -0.2[2 *  (5-1)][ -[0.61]]      

\frac{dT}{dt} = -0.8 +0.84 + 0.976  

\frac{dT}{dt} = 1.016 ^oC/m  

5 0
3 years ago
A neurogenic bladder is a urinary problem caused by interference with the normal __________ associated with urination.
Elena L [17]

Answer:

nerve pathways

Explanation:

It is called Neurogenic Bladder (VN) to any alteration of bladder behavior due to a pathology of the central and / or peripheral nervous system. It may consist of the loss of storage and / or urine disposal capabilities. Thus, a lesion in the upper centers causes variation in storage capacity, but if peripheral innervation is affected, loss of emptying capacity occurs. In the case of patients with spinal cord injury (ML) there are changes in both at the same time.

3 0
4 years ago
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