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Tems11 [23]
3 years ago
7

Yoon Ki investigates electromagnetic induction by moving a bar magnet into a coil of wire. His experimental setup is shown.

Physics
2 answers:
Karolina [17]3 years ago
4 0

A change that would most improve his results would be; D) Connecting the galvanometer to the coil

Snezhnost [94]3 years ago
4 0

Answer: The correct answer is "connecting the galvanometer to the coil".

Explanation:

Electromagnetic induction is the phenomenon of the production of the electromagnetic force across the conductor by changing the magnetic field.

The current can be induced by moving the conductor in the magnetic field. The current can also be induced by changing the magnetic field across the conductor.

The current will be induced into a coil of wire by moving a bar magnet into a coil of wire. It can be observed by connecting the galvanometer to the coil. The galvanometer is an instrument which shows the deflection when the current is flowing in the conductor.

Therefore, the correct option is (D).

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A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,
muminat

Answer:

The speed of the plank relative to the ice is:

v_{p}=-0.33\: m/s

Explanation:

Here we can use momentum conservation. Do not forget it is relative to the ice.

m_{g}v_{g}+m_{p}v_{p}=0 (1)

Where:

  • m(g) is the mass of the girl
  • m(p) is the mass of the plank
  • v(g) is the speed of the girl
  • v(p) is the speed of the plank

Now, as we have relative velocities, we have:

v_{g/b}=v_{g}-v_{p}=1.55 \: m/s (2)

v(g/b) is the speed of the girl relative to the plank

Solving the system of equations (1) and (2)

45v_{g}+168v_{p}=0

v_{g}-v_{p}=1.55

v_{p}=-0.33\: m/s

I hope it helps you!      

8 0
2 years ago
A sample has a density of 30 g/ml. there is 60 ml of this substance.how much does it weigh?
aleksandrvk [35]
If each mL has 30 grams of the substance in it, then 60 mL have 1800 grams of mass in them. the weight of 1,800 grams of mass on Earth is (1.8 kg) x (9.8 m/s^2) = 17.6 newtons.
3 0
3 years ago
A cannon fires a 0.2 kg shell with initial velocity vi = 9.2 m/s in the direction θ = 46 ◦ above the horizontal. The shell’s tra
Sedbober [7]

Answer:

∆h = 0.071 m

Explanation:

I rename angle (θ) = angle(α)

First we are going to write two important equations to solve this problem :

Vy(t) and y(t)

We start by decomposing the speed in the direction ''y''

sin(\alpha) = \frac{Vyi}{Vi}

Vyi = Vi.sin(\alpha ) = 9.2 \frac{m}{s} .sin(46) = 6.62 \frac{m}{s}

Vy in this problem will follow this equation =

Vy(t) = Vyi -g.t

where g is the gravity acceleration

Vy(t) = Vyi - g.t= 6.62 \frac{m}{s} - (9.8\frac{m}{s^{2} }) .t

This is equation (1)

For Y(t) :

Y(t)=Yi+Vyi.t-\frac{g.t^{2} }{2}

We suppose yi = 0

Y(t) = Yi +Vyi.t-\frac{g.t^{2} }{2} = 6.62 \frac{m}{s} .t- 4.9\frac{m}{s^{2} } .t^{2}

This is equation (2)

We need the time in which Vy = 0 m/s so we use (1)

Vy (t) = 0\\0=6.62 \frac{m}{s} - 9.8 \frac{m}{s^{2} } .t\\t= 0.675 s

So in t = 0.675 s  → Vy = 0. Now we calculate the y in which this happen using (2)

Y(0.675s) = 6.62\frac{m}{s}.(0.675s)-4.9 \frac{m}{s^{2} }  .(0.675s)^{2} \\Y(0.675s) =2.236 m

2.236 m is the maximum height from the shell (in which Vy=0 m/s)

Let's calculate now the height for t = 0.555 s

Y(0.555s)= 6.62 \frac{m}{s} .(0.555s)-4.9\frac{m}{s^{2} } .(0.555s)^{2} \\Y(0.555s) = 2.165m

The height asked is

∆h = 2.236 m - 2.165 m = 0.071 m

6 0
3 years ago
In order to increase the speed in a gear system
Ludmilka [50]

Answer:

the driving gear must be larger than the driven gear

Explanation:

6 0
2 years ago
A golden retriever is sitting in a park when it sees a squirrel. The dog starts running, exerting a constant horizontal force of
oksano4ka [1.4K]

Answer:

284.8 kgm/s

Explanation:

Impulse: This can be defined as the product of force and time of a body. The S.I unit of impulse is N.s mathematically.

Impulse = Force × time

Change in momentum: This is the product of the mass of a body and its change in velocity. The unit of change in momentum is kgm/s.

Mathematically,

momentum = mass×change in velocity

Deduction from newton's second law of motion,

Impulse = change in momentum

Therefore,

Change in Momentum = Force×time

ΔM = F×t................. Equation 1

Where F = force = 89 N, t =time =  3.2 s.

Substitute into equation 1

ΔM = 89×3.2

ΔM = 284.8 kgm/s

Thus the change in momentum = 284.8 kgm/s

8 0
3 years ago
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