9514 1404 393
Answer:
Step-by-step explanation:
The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...
∠QSR = 2×∠QTR
∠QSR = 2×39°
∠QSR = 78°
__
Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...
∠QSR + 2(∠SQR) = 180°
78° + 2(∠SQR) = 180° . . . . fill in the value we know
2(∠SQR) = 102° . . . . . . . . . subtract 78°
∠SQR = 51° . . . . . . . . . . . . .divide by 2
Answer:
17 cm
Step-by-step explanation:
P=2L+2W
L=22, P=78 we want to find W
78=2(22)+2W
78=44+2W
34=2W
W=17 cm
Answer:
Step-by-step explanation:
The formula for <u>exponential growth</u> is y = ab^x.
To write this equation, we know it has to start with 48 (which is the variable a). We need to add the rate of growth. This is 11/6 (which is variable b). But we also need to account for the "every 3.5 years" part, so divide the x as an exponent by 3.5.
N(t) = 48 * 11/6^(t/3.5)
This equation is easy to test, and it's a good idea to test it after you write it. For example, after 3.5 years we know that it should have 48*11/6 branches. Does our equation work? Yes.
Lets x = missing angle
x = 180 - (60+80)
x = 180 - 140
x = 40
answer
40
<span>¿Sólo entiendes español o puedo responder en inglés?</span>
