Solution:- Given numbers to compare are 512 and 521 .
As they are 3 digit numbers
So, we have to compare hundreds place.
But hundreds are equal in both the numbers with digit 5.
Next we have to compare tens place.
Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .
So we get the result that,
512 is smaller than 521
or <em> 512 < 521</em>
Case 2:-2 tens is greater in 521 than 1 ten in 512 .
So we get the result that,
521 is greater than 512
or <em> 521 > 512</em>
Answer:
JML=142 degrees
Step-by-step explanation:
This shape is a rhombus, as all 4 sides are equal, but the angle measures are not. One of the properties of a rhombus is that opposite angles are congruent, and adjacent angles are supplementary. Only the second one is important. Since angles KLM and angle JML are supplementary, the equation KLM+JML=180 can be used. KLM is then substituted by the given angle measure, 38 degrees, to get an equation such as JML+38=180. Now, to solve for JML, 38 must be subtracted from both sides of the equation, which leaves teh answer of JML=142.
Answer:
3
Step-by-step explanation:
the initial statement is
y
∝
1
/x
to convert to an equation multiply by k the constant
of variation
y
=
k
×
1
/x
=
k
/x
to find k use the given condition
y
=
5 when x
=
6
y
=
k/
x
⇒
k
=
y
x
=
5
×
6
=
30
y
=
30
/x
when
x
=
10
then
y
=
30
/10
=
3
Where is the question? I would be more than happy to help you but you did not post a question
