The solutions to the system of equations are given as follows: (1, -3) and (-4,2).
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
The equations are given as follows:
- (x + 3)² + (y + 2)² = 17.
From the second equation:
y = -2 - x.
Replacing in the first:
(x + 3)² + (y + 2)² = 17.
(x + 3)² + (-2 - x + 2)² = 17
x² + 6x + 9 + x² = 17
2x² + 6x - 8 = 0
2(x² + 3x - 4) = 0
2(x + 4)(x - 1) = 0.
Then the solutions for x are:
The solutions for y are:
- When x = 1, y = -2 - 1 = -3.
- When x = -4, y = -2 -(-4) = 2.
Hence the solutions are:
(1, -3) and (-4,2).
More can be learned about a system of equations at brainly.com/question/24342899
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Answer:
C
Step-by-step explanation:
Answer:
The system of linear equations are
and 
Step-by-step explanation:
Given : The number of students who chose lunch was 5 more than the number of students who chose breakfast. Let x represent the number of students who chose breakfast and y represent the number of students who chose lunch.
(50 students picked, 25 picked dinner the rest picked lunch and breakfast)
To find : Write a system of linear equations that represents the numbers of students who chose breakfast and lunch ?
Solution :
The number of students who chose breakfast be 'x'
The number of students who chose lunch be 'y'.
The number of students who chose lunch was 5 more than the number of students who chose breakfast.
i.e. 
Now, Total student were 50 and 25 picked dinner the rest picked lunch and breakfast i.e. 25.
So, 
Therefore, the system of linear equations are
and 
<span>To find the slope, you divide the difference of the y-coordinates of a point on a line by the difference of the x-coordinates. It is expressed as:
slope = (y2 - y1) / (x2-x1)
slope = 8-(-7) / 4 - 4
slope = 15 / 0
slope = undefined <------ SECOND OPTION
The line should be vertical where the slope is undefined. Hope this answers the question. Have a nice day.</span>
Answer:
800
Step-by-step explanation: