Answer:
$28,533.5
Explanation:
Principal value (PV) = $275,000
Time = 20 years
Rate = 8.25%
Present Value = P ((1-(1+R)^-n) / r)
275,000 = P ((1- (1 + 0.0825)^-20) /.0825)
275,000 x .0825 = P (1-(1/1.0825)^20)
22687.5 = P ((1.0825^20 - 1) / (1.0825 ^20))
22687.50 = P (4.8816 - 1 / 4.8816)
22687.5 = P (3.886 / 4.8816)
22687.5 = p(0.7951)
P = 22687.5 / 0.7951
P = $28533.5
Answer:
A) Product Differentiation
Explanation:
Product differentiation is referred as a strategy which companies or firms use to showcase the abilities which their products have and the competing product does not have. Some go as far as displaying an added advantage which their products have. Forms which this strategy can take may be through price of the product, reliability of the product or location of the product.
boost frequencies below 80 Hz
What is frequencies?
The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated. The period is the reciprocal of the frequency since it is the length of time for one cycle in a repeating occurrence. For instance, the period, T—the space between beats—of a heart beating at a frequency of 120 beats per minute (2 hertz), is equal to 0.5 seconds (60 seconds divided by 120 beats).
Learn more about frequencies with the help of given link:-
brainly.com/question/17264163
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Answer and Explanation:
The computation of the service level and the corresponding optimal stocking level is shown below:
Given that
Selling price = SP = $4.50
Cost price = CP = $3.00
So,
Salvage value = V = $1.50
Average daily demand (d) = 35 quarts
The standard deviation of daily demand = 4 quarts
based on the above information
Overage cost = (Co) is
= CP - V
= $3.00 - $1.50
= $1.50
Now
Underage cost= (Cu)
= SP - CP
= $4.50 - $3.00
= $1.50
So,
Service level is
= Cu ÷ (Co + Cu)
= 1.50 ÷ (1.50 + 1.50)
= 1.50 ÷ 3.00
= 0.50
= 50%
Now
At 50 % service level, the value of Z is 0
So,
Optimal stocking level is
= d + Z × standard deviation
= 35 + (0 × 4)
= 35 + 0
= 35 quarts