Answer:
y-axis
Step-by-step explanation:
The x-coordinate is the location of a point as measured along the x-axis. The y-coordinate is the location of a point as measured along the y-axis.
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Another way to describe the y-coordinate is that it <em>tells you how far to move from the origin parallel to the </em><em>y-axis</em>.
5y - 16 + 3y + 20 = 180 degrees
Combine like terms on the left side
8y + 4 = 180
Subtract 4 from both sides.
8y = 176
Divide both sides by 8
y = 22
Plug 22 into y for each angle.
3y + 20 = 3(22) + 20 = 66 + 20 = 86 degrees
5y - 16 = 5(22) - 16 = 110 - 16 = 94
The angle opposite 5y - 16 also equals 94 because they are vertical angles.
The angle opposite of 3y + 20 also equals 86 because they are vertical angles
First, turn the mixed numbers into improper fractions.
7 7/9 = 70/9
7 4/5 = 39/5
Second, find common denominators.
70/9 = 350/45
39/5 = 351/45
351/45 > 350/45
Therefore, 7 4/5 is greater.
Best of Luck!
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
