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3 years ago

MARKING BRAINLIEST AND +50 PTS IF CORRECT!!!!

Mathematics

1 answer:

Sphinxa [80]3 years ago

4 0

Answer:If you have two parallel lines and shift both to the left by the same amount, that does not alter the distance between the lines. Thus, c is correct.

Step-by-step explanation:

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Divide. Write your answer as a fraction or mixed number in simplest form.<br><br> 10 • 3 3/4

Citrus2011 [14]

Answer:

37 1/2

Step-by-step explanation:

before you multiply you fractions you would have to change the mixed number into a improper fraction and then multiply your fractions together. once that is dont you would multiply they numerator straight across and multiply the denominator straight across. once that is done your answer should come out as 150/4 but that is a improper fraction and you have to change it into a mixed number which would be 37 2/4 but that can be simplified by 2 and once you simplify it your final answer would come out to be 37 1/2.

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2 years ago

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A ticket to a particular theme park regularly costs $84.99, however the theme park is running a spring break special for 15% off

Ilya [14]

Answer: 306.30

Step-by-step explanation:

DiscountPrice = 84.99 - (84.99 x 0.15)

Cost for 4 = discountPrice x 4

Total = cost for 4 x 1.06

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2 years ago

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A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$