Answer:
a) Change in temperature of the freezing point is +5.35C.
b) The molality of the hydrocarbon is 0.265 M
c) Mass of cyclohexane is 0.014354 g
d) The number of moles of hydrocarbon in the solution is
e) Molar mas of hydrocarbon is .
Explanation:
a)
Therefore, Change in temperature of the freezing point is +5.35C.
b)
Therefore, The molality of the hydrocarbon is 0.265 M.
c)
Therefore, Mass of cyclohexane is 0.014354 g
d)
Therefore, The number of moles of hydrocarbon in the solution is
e)
Therefore, Molar mas of hydrocarbon is .
Answer:
0.474 moles of C₆H₆OS
Explanation:
Step 1: Write the balanced equation
2 C₆H₆OS + 11 O₂ ⇒ 12 CO + 6 H₂O + 2 SO₃
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of C₆H₆OS to SO₃ is 2:2.
Step 3: Calculate the moles of C₆H₆OS reacted if 0.474 moles of SO₃ are produced
We will use the previously established molar ratio.
0.474 mol SO₃ × 2 mol C₆H₆OS/2 mol SO₃ = 0.474 mol C₆H₆OS
Answer:
H2 SO4 (Sulfuric acid) - HMnO4 (Permanganic acid) - HNO2 (Nitrous acid) HClO4 (Perchloric acid) - H2 SO3 (Sulphurous acid) - H2CrO4 (Chromic acid) H2CO3 (Carbonic acid) - HClO3 (Chloric acid) - H3BO3 (boric acid) - HClO2 (Chlorous acid) H3PO4 (Phosphoric acid) HNO3 (Nitric acid) - HClO (Hypochlorous acid) - CH3 COOH (acetic acid) - H2S2O3 (Thiosulfuric acid)- H2C2O4 (oxalic acid)
Explanation:
To name the ternary acid, they have to obbey the following formula
Hx - Non metal - Oy
where the oxidation state in H and O are +1 y -2 respectively.
When the oxidation state of the central Non metal is odd, the atomicity of H is 1 and in the O is deduced in such a way that the sum of oxidation states is 0.
When the oxidation state of the central No metal is even, the atomicity of H is 2 and in the O is deduced in such a way that the sum of oxidation states is 0.
IV V VI VII
- - 1 Hypo ……. Ous
- 3 4 3 … ous
4 5 6 5 … ic
7 Per …… Ous
The oxalic acid is an organic compound of two carboxyl groups, so it is also called ethanedioc acid; It is actually known as oxalic by some plants of the genus oxalis. (prefix et (2 carbons))
The acetic acid that comprises a carboxylic group and a methyl group is also an organic compound. It is popularly known as acetic acid but it is actually called methylcarboxylic acid or having two carbons, ethanoic acid.
Answer:
Explanation:
Mixing Ammonia gas into a solution of Copper(II) Sulfate will give Ammonium Sulfate and a precipitate of Copper(II) Hydroxide (Cu(OH)₂). The Ksp of Cu(OH)₂ is published => 2.2 x 10⁻²². Such gives a solubility* of the Cu(OH)₂ to be ~1.77 x 10⁻⁷M => [Cu⁺²] ~1.77 x 10⁻⁷M and [OH⁻] = 2(1.77 x 10⁻⁷)M = 3.53 x 10⁻⁷M. The reaction of Ammonium Hydroxide and Copper(II) Sulfate will generate 1 x 10⁻⁴ mole Cu(OH)₂ as a precipitate but only 1.77 x 10⁻⁷ mole of the hydroxide will remain in 1 Liter of solution b/c of extreme limited solubility.
*Solubility of 1:2 ionization ratio salts = CubeRt(Ksp/4).
Answer is "0.05 mol".
<em>Explanation;</em>
We can do calculation by using a simple formula as
n = m/M
Where, n is the number of moles of the substance (mol), m is the mass of the substance (g) and M is the molar mass of the substance (g/mol).
Here,
n = ?
m = 2.80 g
M = 56.08 g/mol
By substitution,
n = 2.80 g /56.08 g/mol
n = 0.0499 mol ≈ 0.05 mol