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victus00 [196]
4 years ago
9

Name the following ternary acids. a. H2 SO4 e. HMnO4 i. HNO2 m. HClO4 b. H2 SO3 f. H2 CrO4 j. H2 CO3 n. HClO3 c. H2 S2 O3 g. H3

BO3 k. H2 C2 O4 o. HClO2 d. H3 PO4 h. HNO3 l. CH3 COOH p. HClO
Chemistry
1 answer:
kodGreya [7K]4 years ago
3 0

Answer:

H2 SO4 (Sulfuric acid) - HMnO4 (Permanganic acid) - HNO2 (Nitrous acid) HClO4 (Perchloric acid) - H2 SO3 (Sulphurous acid) - H2CrO4 (Chromic acid)  H2CO3 (Carbonic acid) - HClO3 (Chloric acid) - H3BO3 (boric acid) - HClO2 (Chlorous acid) H3PO4 (Phosphoric acid)  HNO3 (Nitric acid) - HClO (Hypochlorous acid) - CH3 COOH (acetic acid) - H2S2O3 (Thiosulfuric acid)- H2C2O4 (oxalic acid)

Explanation:

To name the ternary acid, they have to obbey the following formula

Hx - Non metal - Oy

where the oxidation state in H and O are +1 y -2 respectively.

When the oxidation state of the central Non metal is odd, the atomicity of H is 1 and in the O is deduced in such a way that the sum of oxidation states is 0.

When the oxidation state of the central No metal is even, the atomicity of H is 2 and in the O is deduced in such a way that the sum of oxidation states is 0.

IV V VI VII  

- - 1 Hypo ……. Ous  

- 3 4 3 … ous  

4 5 6 5 … ic  

  7 Per …… Ous  

The  oxalic acid is an organic compound of two carboxyl groups, so it is also called ethanedioc acid; It is actually known as oxalic by some plants of the genus oxalis. (prefix et (2 carbons))

The acetic acid that comprises a carboxylic group and a methyl group is also an organic compound. It is popularly known as acetic acid but it is actually called methylcarboxylic acid or having two carbons, ethanoic acid.

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When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)
katen-ka-za [31]

Answer:

3.81 g Pb

Explanation:

When a lead acid car battery is recharged, the following half-reactions take place:

Cathode: PbSO₄(s) + H⁺ (aq) + 2e⁻ → Pb(s) + HSO₄⁻(aq)  

Anode: PbSO₄(s) + 2 H₂O(l) → PbO₂(s) + HSO₄⁻(aq) + 3H⁺ (aq) + 2e⁻

We can establish the following relations:

  • 1 A = 1 c/s
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Suppose a current of 96.0A is fed into a car battery for 37.0 seconds. The mass of lead deposited is:

37.0s.\frac{96.0c}{s} .\frac{1mole^{-} }{96468c} .\frac{1molPb}{2mole^{-} } .\frac{207.2gPb}{1molPb} =3.81gPb

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