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amid [387]
3 years ago
5

A sample of matter must be copper if(1) each atom in the sample has 29 protons

Chemistry
1 answer:
butalik [34]3 years ago
3 0
<span>The answer is 1. Copper is an element with sign Cu and atomic number 29 which means that there are 29 protons in this element. It is a soft, flexible, and elastic metal with very extraordinary thermal and electrical conductivity. A newly unprotected exterior of pure copper has a reddish-orange color. </span>
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Can you guys please help me I will mark brainliest to whoever answers this right.
Sphinxa [80]
Wants: a stove top- you don’t need it to make food but it’s more convenient.
Wants: automobile- you don’t need a car but it’s easy to go places and faster. You could use a bike instead however it’s not as convenient to some of us.

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7 0
3 years ago
250 ml of seawater and we inked each molecule with pink color, then we mixed this 250 ml in the ocean. After mixing you took 250
Marysya12 [62]

Answer:

9.77 × 10⁹ molecules

Explanation:

Since the density of water is 1 g/cm³ = 1000 g/L

So, we find the mass of sea water in 250 mL = 0.250 L

We know density = mass/volume

mass = density × volume = 1000 g/L × 0.250 L = 250 g

Now we calculate the number of moles of sea water in 250 g, 250 mL of sea water.

number of moles n = mass of sea water,m/molar mass of water, M

molar mass of water, M = 18 g/moL

n = m/M = 250 g/18 g/mol = 13.89 mol

We now calculate the number of molecules present in the 250 mL of sea water.

n = N/N' where N = number of molecules, N' = avogadro's number = 6.022 × 10²³/mol

So,N =nN' = 13.89 mol × 6.022 × 10²³/mol = 8.36 × 10²⁴ molecules

Now, the volume of the ocean is 1.337 × 10¹⁸ m³ = 1.337 × 10¹⁵ L

Since the 250 mL sea water is mixed with the ocean, the number of molecules per liter is 8.36 × 10²⁴ molecules/1.337 × 10¹⁵ L = 6.25 × 10⁹ molecules/L

If we now take 250 mL out of the ocean, the number of molecules in this 250 mL will be 6.25 × 10⁹ molecules/L × 250 mL =  6.25 × 10⁹ molecules/L × 0.250 L = 9.77 × 10⁹ molecules.

So, we have 9.77 × 10⁹ molecules of pink molecules in the 250 mL after mixing in the ocean.

6 0
3 years ago
How many elements are there
yawa3891 [41]
There are 118 known elements
4 0
4 years ago
Can someone please help me with this? This is due today, please please help me!
Elanso [62]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2>

ATOMIC NUMBER: It is the number of protons present in the nucleus of every atom

MASS NUMBER: It is the number of nucleon. Nucleon are the number of proton and neutrons present in the nucleus.

PROTON NUMBER: Proton number equal to the atomic number.

ELECTRON NUMBER: Electron Number is equal to the atomic number.

NEUTRON NUMBER: It is Mass Number - Atomic Number.

CHARGE: It is due to the addition or removal of the electron. + charge when electron removed and - charge when electron is added.

SYMBOL: It is represented as,

                                                X^Z_A

Z is Mass Number

A is Atomic Number

<h2>_____________________________________</h2><h2>Worksheet:</h2>

(I) ATOMIC NUMBER: 17

    MASS NUMBER: 35.5

    PROTON NUMBER: 17

    ELECTRON NUMBER: 17

    NEUTRON NUMBER: 18.5

    CHARGE: 0

<h2>_____________________________________</h2>

(II) ATOMIC NUMBER: 71

    MASS NUMBER: 180

    PROTON NUMBER: 71

    ELECTRON NUMBER: 71

    NEUTRON NUMBER: 109

    CHARGE: 0

<h2>_____________________________________</h2>

(III)  ATOMIC NUMBER: 40

    MASS NUMBER: 86

    PROTON NUMBER: 40

    ELECTRON NUMBER: 38

    NEUTRON NUMBER: 46

    CHARGE: +2

<h2>_____________________________________</h2>

(IV)  ATOMIC NUMBER: 92

    MASS NUMBER: 238

    PROTON NUMBER: 92

    ELECTRON NUMBER: 86

    NEUTRON NUMBER: 146

    CHARGE: +6

<h2>_____________________________________</h2>

(V) ATOMIC NUMBER: 82

    MASS NUMBER: 206

    PROTON NUMBER: 82

    ELECTRON NUMBER: 78

    NEUTRON NUMBER: 124

    CHARGE: +4

<h2>_____________________________________</h2>

(VI) ATOMIC NUMBER: 34

    MASS NUMBER: 79

    PROTON NUMBER: 34

    ELECTRON NUMBER: 36

    NEUTRON NUMBER: 45

    CHARGE: -2

<h2>_____________________________________</h2>

(VII) ATOMIC NUMBER: 48

    MASS NUMBER: 113

    PROTON NUMBER: 48

    ELECTRON NUMBER: 49

    NEUTRON NUMBER: 65

    CHARGE: -1

<h2>_____________________________________</h2>

(VIII) ATOMIC NUMBER: 21

    MASS NUMBER: 42

    PROTON NUMBER: 21

    ELECTRON NUMBER: 21

    NEUTRON NUMBER: 21

    CHARGE: 0

<h2>_____________________________________</h2>

(IX) ATOMIC NUMBER:

    MASS NUMBER:

    PROTON NUMBER:

    ELECTRON NUMBER:

    NEUTRON NUMBER:

    CHARGE:

<h2>_____________________________________</h2>

(X) ATOMIC NUMBER: 83

    MASS NUMBER: 209

    PROTON NUMBER: 83

    ELECTRON NUMBER: 80

    NEUTRON NUMBER: 126

    CHARGE: +3

<h2>_____________________________________</h2>

(XI) ATOMIC NUMBER: 47

    MASS NUMBER: 108

    PROTON NUMBER: 47

    ELECTRON NUMBER: 47

    NEUTRON NUMBER: 61

    CHARGE: 0

<h2>_____________________________________</h2>

(XII) ATOMIC NUMBER: 49

    MASS NUMBER: 116

    PROTON NUMBER: 49

    ELECTRON NUMBER: 46

    NEUTRON NUMBER: 67

    CHARGE: +3

<h2>_____________________________________</h2>

(XIII) ATOMIC NUMBER: 53

    MASS NUMBER: 128

    PROTON NUMBER: 53

    ELECTRON NUMBER: 54

    NEUTRON NUMBER: 75

    CHARGE: -1

<h2>_____________________________________</h2>

(XIV) ATOMIC NUMBER: 76

    MASS NUMBER: 188

    PROTON NUMBER: 76

    ELECTRON NUMBER: 72

    NEUTRON NUMBER: 112

    CHARGE: +4

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
4 0
3 years ago
A sample of sugar (C12H22O11) contains 1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample?
saveliy_v [14]

Answer: Option (a) is correct.

Explanation:

Molecules of sugar given = 1.505 \times 10^{23}

According to Avogadro's number it is known that 1 mole contains 6.023 \times 10^{23}.

Therefore, calculate the moles of sugar present in the sample as follows.

   Number of moles =  \frac {1.505 \times 10^{23}}{6.023 \times 10^{23}}

           = 0.25 mol

Thus, the moles of sugar present in the sample is 0.25 mol.

6 0
3 years ago
Read 2 more answers
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