Hey There!
Lets Just Work through your answers,
ⓧ A - An isosceles triangle is a triangle with (at least) two equal sides, so this would not apply to the given triangle.
:) B - A scalene triangle is a triangle in which all three sides have different lengths so this applies to the given triangle. One side measures 10, one measures 11, and one measures 12.1
ⓧ C - A right triangle is a type of triangle that has one angle that measures 90 degrees, which this triangle does not so this does not apply.
ⓧ D - In geometry, an equilateral triangle is a triangle in which all three sides are equal, so this does not apply to the given triangle.
ⓧ E - An obtuse triangle is a triangle with one obtuse angle (greater than 90°) and two acute angles, so this does not apply to the given triangle.
:) F - An acute triangle (or acute-angled triangle) is a triangle with three acute angles less than 90 degrees. So this applies to the given triangle.
In Summary, B & F classify the given triangle correctly.
If you could rate five starts & give brainliest that would be greatly appreciated!
Hope I helped, Have a good day.
Answer:
16 - 5 
Step-by-step explanation:
Answer:
<em>71.6 degrees </em>
Step-by-step explanation:
The formula for calculating the angle between two vectors is expressed as;
u.v = |u||v|cos theta
u.v = (8, 4).(9, -9)
u.v = 8(9)+4(-9)
u.v = 72-36
u.v = 36
|u| = √8²+4²
|u| = √64+16
|u| = √80
|v| = √9²+(-9)²
|v| = √81+81
|v| = √162
36 = √80*√162 cos theta
36 = √12960 cos theta
36 = 113.84 cos theta
cos theta = 36/113.84
cos theta = 36/113.84
cos theta = 0.3162
theta = arccos (0.3162)
<em>theta = 71.6 degrees </em>
<em>Hence the angle between the given vectors is 71.6 degrees </em>
3y+4+3y-y=-6
6y-y+4=-6
5y+4=-6
5y=-10
y=-2
If you have any questions let me know
Answer:
the answer is 4k+2h=14 the andwer
