The answer is a ik for a fact
Answer:
10
Explanation:
Given endpoints:
E (-2,2) and F(4, -6)
To find the distance between two points;
Use the expression below;
D = 
x₁ = -2,
x₂ = 4
y₁ = 2
y₂ = -6
Insert the parameters and solve;
D = 
D = 
= 10
Answer:
The answer to your question is C = 0.037 cal/g°C
Explanation:
Data
mass of the wire = m = 237 g
temperature 1 = T1 = 25°C
temperature 2 = T2 = 107°C
Heat = Q = 722 cal
Specific heat = C
Process
1.- Write the formula to find the specific heat
Q = mC(T2 - T1)
-Solve for C
C = Q / m(T2 - T1)
2.- Substitution
C = 722 / 237(107 - 25)
3.- Simplification
C = 722 / 237(82)
C = 722 / 19434
4.- Result
C = 0.037 cal/g°C
Answer:
-1190.24 kJ
Explanation:
The enthalpy change in a chemical reaction that produces or consumes gases is given by the expression:
ΔH = ΔU + Δngas RT
where Δn gas is the change of moles of gas, R is the gas constant,and T is temperature.
Now from the given balanced chemical reaction, the change in number of mol gas is equal to:
Δn gas = mole gas products - mole gas reactants = 2 - 5/2 = -1/2 mol
Sionce we know ΔU and the temperature (298 K), we are in position to calculate the change in enthalpy.
ΔH = -1189 x 10³ J + (-0.5 mol ) 8.314 J/Kmol x 298 K
ΔH = -1.190 x 10⁶ J = -1.190 x 10⁶ J x 1 kJ/1000 J = -1.190 x 10³ J
Answer:
Time of vaporization = 0.588 minutes
Explanation:
The latent heat of fusion is the heat required to change the substance from solid (ice) to liquid completely, without further increase in temperature.
The latent heat of vaporization is the heat required to change a liquid to gas completely, without an increase in temperature.
Latent heat of vaporization = 6.8 times Latent heat of fusion
This means that the time it takes for the latent heat of vaporization to complete vaporization is 6.8 times lesser than the time it takes for the latent heat of fusion to complete fusion
Time of vaporization = 6.8 times lesser than time of fusion
Time of vaporization = (time of fusion) ÷ 6.8
where: Time of fusion = 4 minutes
∴ Time of vaporization = 4 ÷ 6.8
Time of vaporization = 0.588 minutes
