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tatiyna
3 years ago
9

It is possible to have more than the maximum amount of solute dissolved in a solvent.

Chemistry
2 answers:
hodyreva [135]3 years ago
6 0

Answer:

B. False

Explanation:

The maximum amount of solute dissolved in a solvent at a certain temperature is the limit, at which if more solute is added, it won't dissolve, but fall to the bottom of the container.

vladimir1956 [14]3 years ago
3 0

B. False

When the maximum amount of solute has been dissolved in a given amount of solvent, we say that the solution is saturated with solute.

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The rare earth elements include A. the lanthanide series and the alkali metals. B. the alkali metals and the transition metals.
Novay_Z [31]
<span>The rare earth elements include the lanthanide series, scandium and yttrium. They are a set of seventeen chemical elements in the periodic table. They really are not that rare but they occur together in nature and are hard to separate from one another.</span>
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3 years ago
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MArishka [77]
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3 years ago
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How many grams of h2 are needed to produce 10.78 g of nh3?
balu736 [363]
Ammonia is formed by a reaction between hydrogen and nitrogen as shown by the equation below.
N2(g) + 3H2(g) = 2NH3(g)
1 mole of ammonia contains 17 g
Therefore 10.78 g of ammonia are equivalent to 10.78/17 = 0.6341 moles
The mole ratio of hydrogen to ammonia is 3 : 2
Therefore, moles of hydrogen used will be  0.6341 × 3/2 = 0.9512 moles
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Thus, the mas of hydrogen will be 0.9512 moles × 2 = 1.9023 g
6 0
4 years ago
Write the cell notation for an electrochemical cell consisting of an anode where Mn (s) is oxidized to Mn2 (aq) and a cathode wh
morpeh [17]

Answer:

Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)

Explanation:

In writing the cell notation for an electrochemical cell, the anode is written on the left hand side while the cathode is written on the right hand side. The two half cells are separated by two thick lines which represents the salt bridge.

For the cell discussed in the question; the Mn(s)/Mn^2+(aq) is the anode while the Co^2+(aq)/Co(s) half cell is the cathode.

Hence I can write; Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)

8 0
3 years ago
If I only want to make 500 mL of a 1.25% bleach solution, how many milliliters of bleach would I need? Show your work or explain
kiruha [24]

Answer:

  6.25 mL

Explanation:

1.25% of 500 mL is ...

  0.0125×(500 mL) = 6.25 mL

Since 1.25% of the 500 mL of solution is bleach, that's how much you need. That amount is 6.25 mL.

4 0
3 years ago
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