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3 years ago

Please help me will mark brainliest (if answered correctly)

Mathematics

1 answer:

Nikitich [7]3 years ago

7 0

Answer:

64 degree and 116 degree

Step-by-step explanation:

4y-44+3y+35=180(Linear pair)

7y=189

y=27

4(27)-44=64

3(27)+35=116

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What is the mixed number for -10.125 Write in simplest form please!

Wittaler [7]

-10 1/8

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3 years ago

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Can someone help me with b and c?

earnstyle [38]

$\bf \textit{Half-Angle Identities}
\\ \quad \\
sin\left(\cfrac{{{ \theta}}}{2}\right)=\pm \sqrt{\cfrac{1-cos({{ \theta}})}{2}}\qquad 
\boxed{cos\left(\cfrac{{{ \theta}}}{2}\right)=\pm \sqrt{\cfrac{1+cos({{ \theta}})}{2}}}$

$\bf tan\left(\cfrac{{{ \theta}}}{2}\right)=
\begin{cases}
\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}
\end{cases}\\\\
-----------------------------\\\\$

$\bf so\qquad 
\begin{cases}
2\cdot \cfrac{1}{8}\implies \cfrac{1}{4}\qquad thus\implies \cfrac{\frac{1}{4}}{2}\implies \cfrac{1}{8}\\\\
2\cdot \cfrac{1}{16}\implies \cfrac{1}{8}\qquad thus\implies \cfrac{\frac{1}{8}}{2}\implies \cfrac{1}{16}
\end{cases}\\\\
-----------------------------\\\\$

$\bf cos\left( \cfrac{\pi }{8} \right)\iff cos\left( \cfrac{\frac{\pi }{4}}{2} \right)
\\\\\\
cos\left( \cfrac{\frac{\pi }{4}}{2} \right)=\pm \sqrt{\cfrac{1+cos\left( \frac{\pi }{4} \right)}{2}}\implies \pm \sqrt{\cfrac{1+\frac{\sqrt{2}}{2}}{2}}\\\\
-----------------------------\\\\
cos\left( \cfrac{\pi }{16} \right)\iff cos\left( \cfrac{\frac{\pi }{8}}{2} \right)
\\\\\\
cos\left( \cfrac{\frac{\pi }{8}}{2} \right)=\pm \sqrt{\cfrac{1+cos\left( \frac{\pi }{8} \right)}{2}}$

and what is $\bf cos\left( \cfrac{\pi }{8} \right) \ ?$ well, you've just got it from the previous exercise :)

8 0

3 years ago

Find the area of the image below .

KATRIN_1 [288]

The answer is: A. 41 square units. Let point F be (6,5). The total area (A0) is the sum of the area (A1) of the right triangle A B F and the area (A2) of the square C D E F: A0 = A1 + A2. The area of the right triangle A B F is: A1 = (B F * A F)/2. From the image: B F = 10 units and A F = 5 units. So: A1 = (10 * 5)/2 = 50/2 = 25 square units. The area of the square is: A2 = C D * D E. From the image: C D = D E = E F = F C = 4 units. So: A2 = 4^2 = 16 units. From here, the total area is: A0 = A1 + A2 = 25 + 16 = 41 square units.

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3 years ago

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At midnight, the temperature was 43.7°F. In the morning, the temperature was −3.6°F. Which statement describes the temperature?

Wewaii [24]

At midnight, the temperature was 43.7 degrees above 0, and in the morning, it was 3.6 degrees below 0

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Find the value of y = 500 -25x for x = { -3, 2, 5}

elena55 [62]

Answer:

575, 450 and 375

Step-by-step explanation:

Find the value of y = 500 -25x

for x = { -3, 2, 5}

Given the function y = 500-25x

When x = -3.

y = 500-25(-3)

y = 500+75

y = 575

When x = 2

y = 500-25(2)

y = 500-50

y = 450

When x = 5

y = 500-25(5)

y = 500-125

y = 375

Hence the required values are 575, 450 and 375

4 0

3 years ago