A=4
B=0
C=7
X=16
This is what I think
By ASA postulate it can be say that the triangle ABC and triangle MRQ are congruent
<h3>What is Angle Sum Property?</h3>
The sum of all three angles(interior) of a triangle is 180 degrees, and the exterior angle of a triangle measures the same as the sum of its two opposite interior angles.
Using Angle Sum Property, in ΔMRQ
<M + <R + <Q= 180
<M + 42 + 85 = 180
<M = 180 -42
<M= 53°
Now, In ΔMRQ and ΔABC
<A= <R ,
<B = <M
AB = MR
Hence, By ASA criteria ΔMRQ ≅ ΔABC
Learn more about this concept here:
brainly.com/question/3486366
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Answer:
Step-by-step explanation:
ABCD is a square.
side = 24 cm
Area of square = side * side = 24 * 24 = 576 cm²
Semicircle:
d = 24 cm
r = 24/2 = 12 cm
Area of semi circle =πr²
= 3.14 * 12 * 12
= 452.16 cm²
Area of shaded region = area of square - area of semicircle + area of semicircle
= 576 - 452.16 + 452.16
= 576 cm²
Perimeter:
Circumference of semicircle = 2πr
= 2 * 3.14 * 12
= 75.36
Perimeter = 2* circumference of semicircle + 24 + 24
= 2 * 75.36 + 24 + 24
= 150.72 + 24 + 24
= 198.72 cm
Hello,
Since the degree of a polynomial is the highest exponent present, the degree of Mei’s polynomial should be 2.
