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2 years ago

What is the following product? (2 square root 7+3 square root 6)(5 square root 2+4 square root 3)

Mathematics

2 answers:

Sophie [7]2 years ago

6 0

Answer: The required product is $10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2.$

Step-by-step explanation: We are given to find the following product :

P = (2 square root 7+3 square root 6)(5 square root 2+4 square root 3).

We will be using the following property of radicals :

$\sqrt a\times \sqrt b=\sqrt{ab}.$

The given product can be written and evaluated as follows :

$P\\\\=(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\\\\=2\sqrt7(5\sqrt2+4\sqrt3)+3\sqrt6(5\sqrt2+4\sqrt3)\\\\=10\sqrt{7\times2}+8\sqrt{7\times3}+15\sqrt{6\times2}+12\sqrt{6\times3}\\\\=10\sqrt{14}+8\sqrt{21}+15\times2\times\sqrt3+12\times3\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2.$

Thus, the required product is $10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2.$

Xelga [282]2 years ago

5 0

$(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\qquad\text{use distributive property}\\\\=(2\sqrt7)(5\sqrt2)+(2\sqrt7)(4\sqrt3)+(3\sqrt6)(5\sqrt2)+(3\sqrt6)(4\sqrt3)\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{4\cdot3}+12\sqrt{9\cdot2}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt4\cdot\sqrt3+12\sqrt9\cdot\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+(15)(2)\sqrt3+(12)(3)\sqrt2\\\\=\boxed{10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2}$

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2 years ago

If Fred’s age now is three times what it was 12 years ago, how old is Fred 12 years ago?

Nikitich [7]

Answer:

Step-by-step explanation:

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1 year ago

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tamaranim1 [39]

Answer:

y=15

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Step-by-step explanation:

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2 years ago

An instructor gives her class the choice to do 7 questions out of the 10 on an exam.

Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

$10C7=\frac{10!}{7!(10-7)!}=120$

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

$(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50$

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

$(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50$

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

$(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10$

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

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2 years ago

A jacket is advertised to be 85% off the original price. If the sale price is $102 what is the original price ?

Jobisdone [24]

The answer would prob around $188.70 because .85x102=86.7 so add that to 102 and u get 188.70 but I'm prob wrong and I have a test on this tomorrow

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2 years ago