Answer with Step-by-step explanation:
Suppose that a matrix has two inverses B and C
It is given that AB=I and AC=I
We have to prove that Inverse of matrix is unique
It means B=C
We know that
B=BI where I is identity matrix of any order in which number of rows is equal to number of columns of matrix B.
B=B(AC)
B=(BA)C
Using associative property of matrix
A (BC)=(AB)C
B=IC
Using BA=I
We know that C=IC
Therefore, B=C
Hence, Matrix A has unique inverse .
Let
x---------> the length of the sides that have the same length in meters
we know that
the perimeter of the figure is equal to
<u>solve for x</u>
therefore
<u>the answer is</u>
Each of the same length side is 
long
Answer:
B
Step-by-step explanation:
Answer:
Step-by-step explanation:
For the function to have a domain of all reals, the denominator cannot have a value of zero. x^2 + 2cx + 14 will not have zero as a root if it has no real solutions. A quadratic equation has no solutions when the discriminant is negative.
b^2 - 4ac < 0
(2c)^2 - 4(1)(14) < 0
4c^2 - 56 < 0
4c^2 < 56
c^2 < 14
The sentence that is true should have something to do with that 10 multiplied by any number is the number being multiplied by 10 with a zero at the end.
All numbers greater than 0 and smaller than 10 multiplied by 10 and their products are
1×10=10
2×10=20
3×10=30
4×10=40
5×10=50
6×10=60
7×10=70
8×10=80
9×10=90
I hope this helps
