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Dmitriy789 [7]
3 years ago
6

Solve the system of equations:

Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0

(-1,-2) \:  \:  \:  \:  \: and \:  \:  \:  \:  \: (3,6) \\ Answer: A

Step-by-step explanation:

y = 2x \\ y =  {x}^{2}  - 3 \\  \\ 2x =  {x}^{2}  - 3 \\  {x}^{2}  - 2x - 3 = 0 \\ (x + 1)(x - 3) = 0 \\ x + 1 = 0 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: x - 3 = 0 \\ x =  - 1 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: x = 3

When x = -1

Substitute x = -1 into y = 2x

y = 2(-1)

y = -2

( -1, -2)

When x = 3

Substitute x = 3 into y = 2x

y = 2(3)

y = 6

( 3, 6)

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(17.50) + (x) + (1.05 + .06x) = 44.52 <em>plugged in all of the values</em>

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8 0
3 years ago
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3 years ago
8 = 4 - 2x<br> - 2x +5 = 17<br> 12= - 3 ( x+ 5)
max2010maxim [7]
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7 0
3 years ago
8th Grade Math Equation. Please help! I accept any type of help!
muminat

Hello from MrBillDoesMath!

Answer:

Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)


Discussion:

Generally, the x-intercept of a function g(x) occurs where g(x) = 0. In our case this is

g(x) = 0   =>

3x^2 - 9 = 0     =>                         (add 9 to both sides of the equation)

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x^2 = 9/3 = 3  =>

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Negative x-intercept = - sqrt(3)



Thank you,

MrB

5 0
3 years ago
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