You have to figure out the highest common factor of each set of values:
9a + 21 = 3(3a + 7)
21b - 49 = 7(3b - 7)
54 - 6c = 6(9 - c)
8a + 32b = 8(a + 4b)
4p + 28q + 8r = 4(p + 7q +2r)
84a - 36b -12c = 6(14a - 6b - 2c)
6p + 9q + 15r = 3(2p + 3q + 5r)
18s - 30t + 54u = 6(3s - 5t + 9u)
Hope this helps :)
Answer:
The answer is "
"
Step-by-step explanation:
Given value:
Temp-maximum=
Temp. minimum = 
It is halfway between 10 am and 10 pm to 4 am.
The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:
where parameters are A, B , C, D, T is the ° C temperature and t is the time (1-24)






D = 7.5 + 3 = 10.5
Its trigonometric function equation that model temperature T hours after midnight in Johannesburg t.

Answer:
2369.86
Step-by-step explanation:
f(36)=3700(1−0.06) ^36/5
2369.857704098921
Answer:
Length = 49.5 unit and width = 49.5 unit
Step-by-step explanation:
Given as , Perimeter of rectangle = 198 unit
so ,as Perimeter of rectangle = 2× ( Length + width)
Or, 198 = 2 × (Length + width)
Or,
= length + width
So, length + width = 99 unit
Now to make area maximum
Length × width = maximum
Or, (99 - width ) × width = maximum
99 Width - width² = maximum Let width = W
Now differentiate both side with respect to W
D(99W - W²)
= 0 as, constant diff is 0
So, 99 - 2w = 0
Or, w = 
Or, w = 49.5 unit and L = 99- 4905 = 49.5 unit Answer
Answer:
BC = 40º
BMC = 40º
Step-by-step explanation: Since the measure the major and minor arcs add up to 360º, just subtract 320 from 360 to find BC which is 40º. <BMC is also 40º because the measure of the arc is equal to its corresponding angle.