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sweet [91]
2 years ago
13

ANSWERRR PLEASEEEE!!!

Physics
2 answers:
GuDViN [60]2 years ago
6 0

Answer:

50N to the left

Explanation:

I'll explain if you ask

jasenka [17]2 years ago
6 0

Answer:

50 newtons to the left

Explanation:

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What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
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Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

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Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

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      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

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