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sweet [91]
2 years ago
13

ANSWERRR PLEASEEEE!!!

Physics
2 answers:
GuDViN [60]2 years ago
6 0

Answer:

50N to the left

Explanation:

I'll explain if you ask

jasenka [17]2 years ago
6 0

Answer:

50 newtons to the left

Explanation:

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Where is the most deposition most likely to occur?
Temka [501]
Wherever a river loses energy
3 0
3 years ago
A 5-kg can of paint is sitting on top of a 2-meter high step ladder. How much work did you do to move the can of paint to the to
Xelga [282]

98J

Explanation:

Given parameters:

Mass of paint can = 5kg

Height of ladder = 2m

Unknown:

Work done = ?

Potential energy = ?

Solution:

Work done in moving the paint is the force applied under gravity to move it through the give height.

Potential energy is the energy due the position of a body at rest.

For this body:

The work done in moving the paint =  Potential energy at the top of ladder = m x  g x h

m is the mass of the pain can

g is the acceleration due to gravity

h is the height of the building

Input the variables;

 Work done = 5 x 9.8 x 2 = 98J

Potential energy  = 98J

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

3 0
3 years ago
If a substance or object has the ability to do work, then it has
LUCKY_DIMON [66]
Energy is the ability to do work.
7 0
3 years ago
Which tools would sara us to find an irregularly shaped objects mass and volume A. a meter stick , a ruler , and water
tester [92]
I think it's D. Usually, to find the volume of an irregularly shaped object, you put it in water with a labeled beaker to measure how much the water rises. The balance would be used to measure the mass in grams.
4 0
2 years ago
If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of t
Ronch [10]

Since the acceleration is constant, the average velocity is simply the average of the initial and final velocities of the body:

v_{avg} = \frac{v_f+v_i}{2}=\frac{30 m/s+13 m/s}{2}=21.5 m/s

We can proof that the distance covered by the body moving at constant average velocity v_{avg} is equal to the distance covered by the body moving at constant acceleration a:

- body moving at constant velocity v_{avg}: distance is given by

S=v_{avg}t = \frac{v_f+v_i}{2}t

- body moving at constant acceleration a=\frac{v_f-v_i}{t}: distance is given by

S=v_i t+ \frac{1}{2}at^2 = v_i t + \frac{1}{2}\frac{v_f-v_i}{t}t^2=(v_i+\frac{1}{2}(v_f-v_i))t=\frac{v_f+v_i}{2}t

7 0
2 years ago
Read 2 more answers
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