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jolli1 [7]
4 years ago
6

The temperature of 20 liters of helium gas is increased from 100°K to 300°K. If the pressure was kept constant, the new volume w

ill be how many liters? a) 6.7 b) 30 c) 60 d) 120 e) None of these
Physics
1 answer:
slavikrds [6]4 years ago
8 0

Answer:

New volume (V2) = 60 liter

Explanation:

Given:

Amount of helium (V1) = 20 Liter

Temperature (T1) = 100°K

Temperature (T2) = 300°K

Find:

New volume (V2)

Computation:

According to Gas Law:

V1 / T1 = V2 / T2

20 / 100°K = V2 / 300°K

V2 = 60 liter

New volume (V2) = 60 liter

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4. Calculate the kinetic energy of a 4.7 kg object moving at a speed of 7 m/s. SHOW YOUR WORK
SashulF [63]

Answer:

\boxed {\boxed {\sf 115.15 \ J}}

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated with the following formula.

E_K= \frac{1}{2} mv^2

The mass of the object is 4.7 kilograms. The velocity of the object is 7 meters per second.

  • m= 4.7 kg
  • v= 7 m/s

Substitute the values into the formula.

E_K= \frac{1}{2} (4.7 \ kg)(7 \ m/s)^2

Solve the exponent.

  • (7 m/s)²= 7 m/s * 7 m/s = 49 m²/s²

E_K= \frac{1}{2} (4.7 \ kg)(49 \ m^2/s^2)

Multiply the numbers together.

E_K = 2.35 \ kg * 49 \ m^2/s^2

E_K= 115.15 \ kg*m^2/s^2

Convert the units. 1 kilogram square meter per square second is equal to 1 Joule.

E_K= 115.15 \ J

The object has <u>115.15 Joules</u> of kinetic energy.

3 0
2 years ago
Read 2 more answers
Suppose that a car traveling to the west (-x direction) begins to slow down as it approaches a traffic light. Make a statement c
nata0808 [166]

Answer:

The car is decelerating and its acceleration is negative.

Explanation:

First thing to consider. The car traveling direction is not important to answer the question.

Second, there are two affirmations on each sentence. So, lets take definitions:

Deceleration: Reducing the acceleration, from one value to another. No matter if the acceleration for the moment is positive or negative.

Acceleration negative: the driver is applying a force to make speed=0, the sign of this force must negative in order for the car to stop, other way it will go faster. Acceleration is the change rate of speed, if the speed is going down, the total acceleration until cars stops must be negative.

4 0
3 years ago
The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles
miss Akunina [59]

Formula of the gravitational force between two particles:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67 \cdot 10^{-11} Nm^2 kg^{-2} is the gravitational constant

m1 and m2 are the masses of the two particles

r is their distance


(a) particle A

The gravitational force exerted by particle B on particle A is

F_B=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=5.14 \cdot 10^{-5} N to the right

The gravitational force exerted by particle C on particle A is

F_C=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=5.6 \cdot 10^{-6} N to the right

So the net gravitational force on particle A is

F_A = F_B + F_C =5.14 \cdot 10^{-5} N+5.6 \cdot 10^{-6} N=5.7 \cdot 10^{-5} N to the right


(b) Particle B

The gravitational force exerted by particle A on particle B is

F_A=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=-5.14 \cdot 10^{-5} N to the left

The gravitational force exerted by particle C on particle B is

F_C=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=8.41 \cdot 10^{-5} N to the right

So the net gravitational force on particle B is

F_B = F_A + F_C =-5.14 \cdot 10^{-5} N+8.41 \cdot 10^{-5} N=3.27 \cdot 10^{-5} N to the right


(c) Particle C

The gravitational force exerted by particle A on particle C is

F_A=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=-5.6 \cdot 10^{-6} N to the left

The gravitational force exerted by particle B on particle C is

F_B=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=-8.41 \cdot 10^{-5} N to the left

So the net gravitational force on particle C is

F_C = F_B + F_A =-8.41 \cdot 10^{-5} N-5.6 \cdot 10^{-6} N=-8.97 \cdot 10^{-5} N to the left



3 0
3 years ago
What factor accounts for the fact that egg floats in salt water
marin [14]
I believe it is because the salt supports the weight of the egg
8 0
3 years ago
Hawk maintains a consistent internal temperature in both the heat of the day in the cool of the night. This is called
jok3333 [9.3K]

Answer

hawk maintains a consistent internal temperature in both the heat of the day and the cool of night this is called as endothermy.

Endothermy also known as warm-bloodedness is defined as the ability of an animal, bird or organism to produce heat and conserve it to maintain a consistent internal temperature.  


8 0
3 years ago
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