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jolli1 [7]
3 years ago
6

The temperature of 20 liters of helium gas is increased from 100°K to 300°K. If the pressure was kept constant, the new volume w

ill be how many liters? a) 6.7 b) 30 c) 60 d) 120 e) None of these
Physics
1 answer:
slavikrds [6]3 years ago
8 0

Answer:

New volume (V2) = 60 liter

Explanation:

Given:

Amount of helium (V1) = 20 Liter

Temperature (T1) = 100°K

Temperature (T2) = 300°K

Find:

New volume (V2)

Computation:

According to Gas Law:

V1 / T1 = V2 / T2

20 / 100°K = V2 / 300°K

V2 = 60 liter

New volume (V2) = 60 liter

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HELP PLS i need this right now
N76 [4]

Answer:

V = 44.4 units.

Explanation:

In order to solve this problem, we must use the Pythagorean theorem. Which is defined by the following expression.

V = \sqrt{(V_{x})^{2} +(V_{y})^{2} }

where:

Vx = - 43 units

Vy = 11.1 units

Now replacing:

V=\sqrt{(-43)^{2} +(11.1)^{2} }\\V=44.4 units

7 0
3 years ago
A heavy meterstick has a mass of 1 kg. When the meterstick is thrown like a spear past you, you measure its momentum to be 2mv.
CaHeK987 [17]

Answer:

Its length is measured to be 0.5 m

Explanation:

From theory of relativity (mass variation), we know that:

m = mo/√(1-v²/c²)

Where, m = relative mass

and, mo = rest mass

The momentum of stick while moving, will be:

P = mv

but, it is given in the form of rest mass as:

P = 2(mo)v

thus, by comparison;

2(mo)v = mv

using value of m from theory of relativity;

2(mo)v = (mo)v/√(1-v²/c²)

√(1-v²/c²) = 1/2     ______ eqn(1)

Now, for relativistic length (L), we have the formula from same theory of relativity;

L = (Lo)√(1-v²/c²)

The rest length (Lo) of meter stick is 1 m, and the remaining term on right side √(1-v²/c²), known as Lorentz Factor, can be given by eqn (1), as equal to 1/2.

Thus,

L = (1 m)(1/2)

<u>L = 0.5 m</u>

4 0
3 years ago
Closed circuit
VMariaS [17]

A. the light bulb goes out once the circuit is open since it causes the flow of electricity to cut off. the light bulb dosent get the energy it needs to light up

Explanation:

B. a simple example of this in our every day life is a light switch. when you switch the light on then the circuit is closed and the energy transfers to the light bulb, when u switch the light off then you cut off the lights source of energy which causes the light to turn off.

5 0
2 years ago
What does a negative value for the focal length tell you?
Llana [10]
 the focal length <span> is much more decent  for a concave, and also worse</span><span> for a convex mirror. When the image that is given, distance is good and decent, images are always on the same area of the mirror as the object given , and it is not fake.  images distance  is </span>never positive <span>, the image is on the oppisite side of  the mirror, so the image must be virtual.</span>
7 0
3 years ago
A student makes a short electromagnet by winding 300 turns of wire around a wooden cylinder of diameter d 5.0 cm. The coil is co
kupik [55]

Answer:

A) μ = A.m²

B) z = 0.46m

Explanation:

A) Magnetic dipole moment of a coil is given by; μ = NIA

Where;

N is number of turns of coil

I is current in wire

A is area

We are given

N = 300 turns; I = 4A ; d =5cm = 0.05m

Area = πd²/4 = π(0.05)²/4 = 0.001963

So,

μ = 300 x 4 x 0.001963 = 2.36 A.m².

B) The magnetic field at a distance z along the coils perpendicular central axis is parallel to the axis and is given by;

B = (μ_o•μ)/(2π•z³)

Let's make z the subject ;

z = [(μ_o•μ)/(2π•B)] ^(⅓)

Where u_o is vacuum permiability with a value of 4π x 10^(-7) H

Also, B = 5 mT = 5 x 10^(-6) T

Thus,

z = [ (4π x 10^(-7)•2.36)/(2π•5 x 10^(-6))]^(⅓)

Solving this gives; z = 0.46m =

3 0
3 years ago
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