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Rina8888 [55]
3 years ago
5

Why won’t anyone help me please anybody help me I really need help .

Physics
1 answer:
irga5000 [103]3 years ago
8 0

Answer:

1➡️ this is the method of decomposition

2➡️ H2 and O2

3➡️ b

sorry if I am wrong

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PLEASE HELP ONLY NINE DAYS LEFT I WILL GIVE BRANLIEST
Snowcat [4.5K]

Answer:

A A A

Explanation:

6 0
2 years ago
I will mark you as brainliest. if you answer my question
Shalnov [3]

First, let's list everything we have...

a = 1.83 m/s^2

F = 1870 N (converted from kN to N)

vi = 0 m/s (it says started from rest, therefore velocity starts at 0)

t = 16 s

1). "Force acting on the car" is a bit ambiguous because there are many forces. But I'm going to assume that they are looking for just a basic implementation of force equation:

F=ma

where:

F = force

m = mass

a = acceleration

2). I recommend memorizing your equations of motion, because once you know them this part is also just as easy:

v_f=v_i+at

where:

vf = final velocity

vi = initial velocity

a = acceleration

t = time

5 0
3 years ago
What is the relationship between wavelength and frequency? is it direct or inverse?
Komok [63]
T<span>he relationship between wavelength and frequency is inverse.

This is as the wavelength increases the frequency decreases and as the wavelength decreases the frequency increases.

The light meets this equation that reflects the relationship between wavelength and frequency:

c = wavelength * frequency => wavelength = c / frequency

where c is the constant speed of light.
</span>
5 0
3 years ago
1-D Kinematics, Constant Acceleration After falling a distance of 45.0 m from the top of a building, a box is landing on the top
Mrrafil [7]

Answer:

Explanation:

Given

Object fall from a height of s=45\ m

Considering initial velocity to be zero i.e. u=0

using

v^2-u^2=2as  

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

v^2-0=2(9.8)\cdot 45

v=29.69\ m/s\approx 29.7\ m/s

(b)Average acceleration

After falling 45 m, object strike the car and comes to rest after covering a distance of 0.5 m

again using

v'^2-u'^2=2as'

here final velocity will be zero i.e.v'=0

initial velocity u'=v

0-(29.7)^2=2\cdot a\cdot 0.5

a=-882.09\ m/s^2

(c)time taken by it to stop

v'=u'+a't

0=29.7-882.09\cdot t

t=0.034\ s

5 0
3 years ago
A car tire rotates at a constant angular velocity of 3.5 rotations during a time interval of 0.75 seconds. What is the angular s
Andru [333]

Answer : \theta = 2.625\ radians

Explanation :  

Given that,

Angular velocity \omega = 3.5\ rad/s

Time t = 0.75 s

We know , the formula of angular velocity

\omega = \dfrac{\theta}{t}

\theta = \omega \times t

\theta = 3.5\ rad/s\times0.75\ s

The angular speed of the tire is

\theta = 2.625\ radians

Hence, this is the required solution.



4 0
3 years ago
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