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3 years ago

Sinplify 6/10x^2÷6/10x^3-60x2

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

8 0

$\cfrac{6}{10x^2}: \cfrac{6}{10x^3-60x^2}= \cfrac{6}{10x^2}*\cfrac{10x^3-60x^2}{6}=\cfrac{10x^3-60x^2}{10x^2}= \\\\\\ =\cfrac{10x^2(x-6)}{10x^2}=x-6$

A. x-6

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Suppose the polynomial function below represents the power generated by a wind turbine, where x represents the wind speed in met

Elis [28]

Answer:

<em>f(10) or the power generated by the wind turbine at the wind speed of 10 m/s is </em><em>190.26 kW</em>

Step-by-step explanation:

The given polynomial function is,

$f(x) = 0.08x^3 + x^2 + x + 0.26$

where,

x represents the wind speed in meters per second,

y represents the kilowatts generated.

Putting x=10, we can get the value of f(10).

So,

$=f(10)$

$= 0.08(10)^3 + (10)^2 + (10) + 0.26$

$= 0.08(1000) + (100) + (10) + 0.26$

$= 80 + 100 + 10 + 0.26$

$=190.26$

Therefore,at x=10 or when the wind speed is 10 m/s, then y or the power generated by the wind turbine will be 190.26 kW

6 0

3 years ago

Read 2 more answers

As the student council treasurer, you prepare the budget for your class rafting trip. Each large raft

Klio2033 [76]

Answer:

10 small rafts

Step-by-step explanation:

(1600- 1200) / 40 = 10

1600- 1200 = 400

400 / 40 = 10

12 large rafts costs $1200 so subtract that amount from you budget. If you do that you will have $400 left. So I divided $400 by the amount of money each small raft cost whitch was $40 per small raft so i got the quotient of 10.

Sorry if i worded that weirdly but you get the point.

P.s sorry if it isn't comlety correct but i did my best so... ya

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3 years ago

Find the polynomial of minimum degree, with real coefficients, zeros at

drek231 [11]

Answer:

$\huge\boxed{p(x)=4x^3-20x^2+4x+300}$

Step-by-step explanation:

$\text{If}\ x=4\pm3i\ \text{and}\ x=-3\ \text{are the zeros of a polynomial, then it has a form:}\\\\p(x)=\bigg(x-(4-3i)\bigg)\bigg(x-(4+3i)\bigg)\bigg(x-(-3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x-4+3i)(x-4-3i)(x+3)\bigg(r(x)\bigg)\\\\p(x)=\underbrace{\bigg((x-4)+3i\bigg)\bigg((x-4)-3i\bigg)}_{\text{use}\ (a+b)(a-b)=a^2-b^2}(x+3)\bigg(r(x)\bigg)\\\\p(x)=\bigg((x-4)^2-(3i)^2\bigg)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2$

$p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)$

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4 years ago

Find the slope C(-8,-7) and D (13,-1

DaniilM [7]

So you will use slope formula which is m = (y2 -- y1) / (x2 -- x1)

-1 minus -7=6

13 minus -8=21

Remember it changes to a positive Keep,Change,Change

So its 6/21

Or 1/4

Ask questions if you still need help

3 0

3 years ago

if a staircase rises 52° from the ground and a vertical distance of 12 yards. How much horizontal distance does the staircase co

3241004551 [841]

The horizontal distance will be found using the formula:
tan θ= opposite/adjacent
given that θ=52°
opposite= 12 yards
adjacent=x
hence
tan 52=12/x
x=12/tan 52
x=9.3754
the height is 9.375 yards

3 0

3 years ago