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wolverine [178]
3 years ago
15

What are the leading coefficient and degree of the polynomial?

Mathematics
1 answer:
MissTica3 years ago
4 0

Answer:

  • leading coefficient: 2
  • degree: 7

Step-by-step explanation:

The degree of a term with one variable is the exponent of the variable. The degrees of the terms (in the same order) are ...

  6, 0, 7, 1

The highest-degree term is 2x^7. Its coefficient is the "leading" coefficient, because it appears first when the polynomial terms are written in decreasing order of their degree:

  2x^7 -7x^6 -18x -4

The leading coefficient is 2; the degree is 7.

__

<em>Additional comment</em>

When a term has more than one variable, its degree is the sum of the exponents of the variables. The term xy, for example, is degree 2.

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Y = x – 6 x = –4 what is the solution to the system of equations? (–8, –4) (–4, –8) (–4, 4) (4, –4
fredd [130]

Answer:

(- 4, - 10 )

Step-by-step explanation:

Given the 2 equations

y = x - 6 → (1)

x = - 4 → (2)

Substitute x = - 4 into (1) for corresponding value of y

y = - 4 - 6 = - 10

Solution is (- 4, - 10 )

4 0
3 years ago
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pentagon [3]
I know you have 1 and 3 right but I'm sorry about not knowing the rest.
8 0
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P is located at (8,-7) and Q is located at (-6,-3) on the coordinate plane
Readme [11.4K]

Answer:

Step-by-step explanation:

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3 years ago
HELP PLEASE <br> solve the right triangle
aleksandrvk [35]

Answer:

Part 1) FG=4.4\ units

Part 2) EF=3.9\ units

Part 3) m\angle G=63^o

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

sin(27^o)=\frac{GE}{FG} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(27^o)=\frac{2}{FG}

FG=\frac{2}{sin(27^o)}=4.4\ units

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

cos(27^o)=\frac{EF}{FG} ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

cos(27^o)=\frac{EF}{4.4}

EF=cos(27^o)(4.4)=3.9\ units

step 3

Find the measure of angle G

we know that

m\angle G+27^o=90^o ---> by complementary angles in a right triangle

m\angle G=90^o-27^o=63^o

7 0
3 years ago
Select ALL the numbers that are greater than 2.
ivanzaharov [21]

Answer: B and D

8/9 • 2 = 1.77

13/11 • 2 = 2.36

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hope this helped :)

6 0
3 years ago
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