1a) The function has arrows on both ends and no place in the middle where it is not defined. Its domain is ...
All Reals
1b) The function gives no output values below -3, but it gives output values of -3 and all above that. Its range is ...
y ≥ -3
1c) For values of x less than -1, the function's output is 1. This matches g(x) and s(x). At x=0, the function's output is -3, which only matches g(x). The appropriate choice is ...
g(x)
2b) The function is only defined for 0 ≤ x < 8. This is its domain.
3) A definition might be ...
Let's see what to do buddy...
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To do this, we have to multiply the face and denominator of the fraction by the denominator conjunction, which is :

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
Reminder :

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
So we have :

The other is in the photo.
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And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Por determinante:
5...1...1
1...0...1 = 0 --> se o determinante for igual a 0, os pontos estarão alinhados.
3...3...1
calculando: (5 x 0 x 1 + 1 x 1 x 3 + 1 x 3 x 1) - (1 x 0 x 3 + 1 x 1 x 1 + 3 x 1 x 5) =
0 + 3 + 3 - 0 - 1 - 15 =
6 - 1 - 15 =
5 - 15 = - 10 --> como não deu zero, os pontos não estão alinhados.