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irina [24]
3 years ago
12

1/3 + (3x+12) = 6x -11

Mathematics
2 answers:
Lerok [7]3 years ago
6 0

Answer:

x = 70/9

Step-by-step explanation:

Pavel [41]3 years ago
6 0

Answer:

70/9

Step-by-step explanation:

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Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0
3 years ago
Read 2 more answers
jordan is cutting a 2 m by 1 1/4 m piece of rectangular paper into two pieces along its diagonal. find the area of each of the p
alexdok [17]

Answer:

The area of a rectangle is 5/4

Step-by-step explanation:

5 0
2 years ago
4<br> Om obtuse, scalene<br> Obright, scalene<br> Oc, right, isosceles<br> Od, right, equilateral
harina [27]

Answer:

B

Step-by-step explanation:

B. right, scalene

3 0
2 years ago
Order the numbers from least to greatest. 3 and thirty nine fortieths, 3 and nineteen twentieths, 3 and one half.
Assoli18 [71]
3 39/40 = 3.975
3 19/20 = 3.95
3 1/2 = 3.5

least to greatest : 3 1/2, 3 19/20, 3 39/40
8 0
3 years ago
If you have 20 coins worth $1.35, and you only have nickels and dimes, how many do you have of each coin?
ankoles [38]
N + d = 20....n = 20 - d
0.05n + 0.10d = 1.35

0.05(20 - d) + 0.10n = 1.35
1 - 0.05d + 0.10d = 1.35
-0.05d + 0.10d = 1.35 - 1
0.05d = 0.35
d = 0.35/0.05
d = 7 <==== 7 dimes

n + d = 20
n + 7 = 20
n = 20 - 7
n = 13 <=== 13 nickels
5 0
3 years ago
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