.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 ) ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
-2a =38
a = -19
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0 .... b = 15
the center is :w(-19,15)
Zero, because ANYTHING to the power of zero equals 1.
Answer:
The formula of a²-b² are as follows:
Step-by-step explanation:
(a-b)(a+b)
Answer:
if you can split it in half its: $38.75
if you cant its: $46.50
Step-by-step explanation:
half:
1. 8+8+4=20
2. 15.50 divided by 2 = 7.75
3. 7.75 + 15.50 + 15.50 = 38.75
not half:
1. 8+8+8= 24
2. 15.50 times 3 = 46.50
First find the slope of f(x).
m=(y2-y1)/(x2-x1)
m=(1-5)/(2-0)
m=-4/2
m=-2
y=-2x+b, using (2,1) we can solve for the y-intercept, "b"
1=-2(2)+b
1=-4+b
5=b
y=-2x+5
So f(x) has a y-intercept of 5
g(x)=6m+3
So g(x) has a y-intercept of 3
h(x)=3x+4
So h(x) has a y-intercept of 4
Then g(x) has the lowest y-intercept of just 3.
