All categories

3 years ago

I need the answer ASAP please

Mathematics

1 answer:

ANTONII [103]3 years ago

3 0

Ok bare with me here.
I’m not sure if you filled in the minimum medium and max but I’m going to try and lay this out.
Min: 3
Q1: 7.5
Med: 9
Q2: 13
Max: 17

I hope this helps!! It should get you through the problem!

You might be interested in

What does 7526.442 round to the nerest hundredth

Viefleur [7K]

7526.44 because you look at the thousanth place (the 2) and since it is less than 5 you round down

7 0

3 years ago

Pls i dont have time help

kvv77 [185]

18 !

27/x = 12/8
Cross multiply and then solve

4 0

3 years ago

Your 8 year loan of $12, 200 with an interest rate of 5.3% is compounded weekly. b) How much will you have paid in interest?

evablogger [386]

Answer:

The final balance is $18,332.79.

The total compound interest is $6,332.79.

Step-by-step explanation:

4 0

3 years ago

!!!!! determine the function being differentiated, and the number at which its derivative is being evaluated. Where possible, ev

Genrish500 [490]

Recall that the derivative of a function f(x) at a point x = c is given by

$\displaystyle f'(c) = \lim_{x\to c} \frac{f(x) - f(c)}{x - c}$

By substituting h = x - c, we have the equivalent expression

$\displaystyle f'(c) = \lim_{h\to0} \frac{f(c+h) - f(c)}h$

since if x approaches c, then h = x - c approaches c - c = 0.

The two given limits strongly resemble what we have here, so it's just a matter of identifying the f(x) and c.

For the first limit,

$\displaystyle \lim_{h\to0} \frac{\sin\left(\frac\pi3 + h\right) - \frac{\sqrt3}2}h$

recall that sin(π/3) = √3/2. Then c = π/3 and f(x) = sin(x), and the limit is equal to the derivative of sin(x) at x = π/3. We have

$(\sin(x))' = \cos(x)$

and cos(π/3) = 1/2.

For the second limit,

$\displaystyle \lim_{a\to0} \frac{e^{2a} - 1}a$

we observe that e²ˣ = 1 if x = 0. So this limit is the derivative of e²ˣ at x = 0. We have

$\left(e^{2x}\right)' = e^{2x} (2x)' = 2e^{2x}$

and 2e⁰ = 2.

8 0

2 years ago

Find missing variable and check: -3(x-6)+4(x+1)=7x-14

lana66690 [7]

We need to solve the equation to find x

$-3(x-6)+4(x+1)=7x-14$

We will simplify the left side by multiply each bracket by the number before it

-3(x - 6) = -3(x) + -3(-6) = -3x + 18

4(x + 1) = 4(x) + 4(1) = 4x + 4

Now put them on the left side

$-3x+18+4x+4=7x-14$

Add the like terms on the left side

$\begin{gathered} (-3x+4x)+(18+4)=7x-14 \\ x+22=7x-14 \end{gathered}$

Now we will collect x on the right side and the numbers on the left side

Subtract x from both sides

$\begin{gathered} x-x+22=7x-x-14 \\ 22=6x-14 \end{gathered}$

Add 14 to both sides

$\begin{gathered} 22+14=6x-14+14 \\ 36=6x \end{gathered}$

Divide both sides by 6 to find x

$\begin{gathered} \frac{36}{6}=\frac{6x}{6} \\ 6=x \end{gathered}$

The value of x is 6

3 0

1 year ago