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Marysya12 [62]
3 years ago
9

4−2(3+7)=4−23−27 Is this true or fasle

Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0

Answer:

false

Step-by-step explanation:

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George walks 1 mile to school. He leaves home at the same time each day, walks at a steady speed of 3 miles per hour, and arrive
alex41 [277]

Answer:

George must run the last half mile at a speed of 6 miles per hour in order to arrive at school just as school begins today

Step-by-step explanation:

Here, we are interested in calculating the number of hours George must walk to arrive at school the normal time he arrives given that his speed is different from what it used to be.

Let’s first start at looking at how many hours he take per day on a normal day, all things being equal.

Mathematically;

time = distance/speed

He walks 1 mile at 3 miles per hour.

Thus, the total amount of time he spend each normal day would be;

time = 1/3 hour or 20 minutes

Now, let’s look at his split journey today. What we know is that by adding the times taken for each side of the journey, he would arrive at the school the normal time he arrives given that he left home at the time he used to.

Let the unknown speed be x miles/hour

Mathematically;

We shall be using the formula for time by dividing the distance by the speed

1/3 = 1/2/(2) + 1/2/x

1/3 = 1/4 + 1/2x

1/2x = 1/3 - 1/4

1/2x = (4-3)/12

1/2x = 1/12

2x = 12

x = 12/2

x = 6 miles per hour

4 0
3 years ago
What is the value of X
Volgvan

Answer:

Step-by-step explanation:

it's another one of those similar triangles

it's easier to see this one.

t /c = u / b

where

t = 7x + 3

c = 27

u = 35

b = 21

plug in the knowns

7x + 3 / 27 = 35 / 21

7x + 3  = 27 ( 35 / 21 )

7x + 3 = 9 ( 35 / 7 )     ( divided by 3 )

7x  + 3  = 9 ( 5)     ( 7 into 35 =5 )

7x  + 3  = 45

7x = 45 - 3

7x = 42  

x = 6

I checked it, the ratio is 1_2/3  :) for both, but you can check it too

7 0
3 years ago
Please answer this question!!
n200080 [17]
B. 273.18  is the correct answer I think.

6 0
3 years ago
Can someone help me please
Neporo4naja [7]

If Deliah does jumping jacks at a constant rate, this means that she does them at the same pace or you could say that she does the same amount of jumping jacks in a specified amount of time, ie. if you counted how many jumping jacks she did in one minute, it would be same as how many she would complete in the next minute, and the next, and so on.

Now given that she does 184 jumping jacks in four minutes, and she has kept a constant pace throughout, to find out how many she does each minute, we simply need to divide the number of jumping jacks she does in 4 minutes by 4. Thus:

Jumping jacks in 1 minute = Jumping jacks in 4 minutes / 4

= 184 / 4

= 46

Thus, Deliah can do 46 jumping jacks per minute.

5 0
3 years ago
Y^-1 dy +ye^(cosx) sinxdx=0
olga nikolaevna [1]
Please see the answer here


http://www.wolframalpha.com/input/?i=y%5E-1%20dy%20%2Bye%5E%28cosx%29%20sinxdx%3D0
3 0
3 years ago
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