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2 years ago

What is the circumference of. circle with a diameter of 16 inches. Do not have round

Mathematics

2 answers:

finlep [7]2 years ago

8 0

Answer:

50.24

Step-by-step explanation:

3.14 times 16

pi times diameter

Komok [63]2 years ago

5 0

Answer:

50.24

Step-by-step explanation:

C= πd

C= 3.14 x 16

C= 50.24

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10 dan büyük doğal sayılar 50 den küçük doğal sayılar 7 nın katı olan pozitif tam sayilar

shtirl [24]

Answer:

yes lul

Step-by-step explanation:

7 0

3 years ago

PLEASE HELPP! ANYONE??? *cry*

Drupady [299]

Answer:

Step-by-step explanation:

As we can see;

10 * ( a + b ) / 9 * ( x - y ) ⇒ 10a + 10b / 9x - 9y

This concludes that the top part of this equation is multiplied by 10 and the bottom by 9. To derive the solution, let us do the same with 3 / 5;

10a + 10b / 9x - 9y = 3 * 10 / 5 * 9

And simplify, to recieve;

10a + 10b / 9x - 9y = 30 / 45 = 6 / 9 = 2 / 3,

<em>Answer: 10a + 10b / 9x - 9y = 2 / 3</em>

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3 years ago

I NEED HELP NOW!!!!

gayaneshka [121]

Answer:

before you asked this question did you look it up

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Suppose a change of coordinates T:R2→R2 from the uv-plane to the xy-plane is given by x=e−2ucos(5v), y=e−2usin(5v). Find the abs

anzhelika [568]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The solution is $\frac{\delta (x,y)}{\delta (u, v)} | = 10e^{-4u}$

Step-by-step explanation:

From the question we are told that

$x = e^{-2a} cos (5v)$

and $y = e^{-2a} sin(5v)$

Generally the absolute value of the determinant of the Jacobian for this change of coordinates is mathematically evaluated as

$| \frac{\delta (x,y)}{\delta (u, v)} | = | \ det \left[\begin{array}{ccc}{\frac{\delta x}{\delta u} }&{\frac{\delta x}{\delta v} }\\\frac{\delta y}{\delta u}&\frac{\delta y}{\delta v}\end{array}\right] |$

$= |\ det\ \left[\begin{array}{ccc}{-2e^{-2u} cos(5v)}&{-5e^{-2u} sin(5v)}\\{-2e^{-2u} sin(5v)}&{-2e^{-2u} cos(5v)}\end{array}\right] |$

$Let \ a = -2e^{-2u} cos(5v), \\ b=-2e^{-2u} sin(5v),\\c =-2e^{-2u} sin(5v),\\d=-2e^{-2u} cos(5v)$

$\frac{\delta (x,y)}{\delta (u, v)} | = |det \left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] |$

=> $\frac{\delta (x,y)}{\delta (u, v)} | = | a * b - c* d |$

substituting for a, b, c,d

=> $\frac{\delta (x,y)}{\delta (u, v)} | = | -10 (e^{-2u})^2 cos^2 (5v) - 10 e^{-4u} sin^2(5v)|$

=> $\frac{\delta (x,y)}{\delta (u, v)} | = | -10 e^{-4u} (cos^2 (5v) + sin^2 (5v))|$

=> $\frac{\delta (x,y)}{\delta (u, v)} | = 10e^{-4u}$

7 0

3 years ago

Please help i think i solved it correctly but i just want to double check

Firlakuza [10]

Subtract 21 from both sides

8 0

3 years ago

Read 2 more answers