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olchik [2.2K]
3 years ago
11

Yesterday, you sent 25 text messages. You said that 20% of those messages were to your best friend. How many text messages did y

ou send to your best friend yesterday?
Mathematics
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

5 text messages

Step-by-step explanation:

Given data

The total number of text= 25

20% of the text message were to your best friend

Let us find 20% of 25

=20/100*25

=0.2*25

=5

Hence the number of text sent to your best friend is 5 text messages

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Estimate then find the sum 63,824+29,452​
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90,000 becuase 63,824 is rounded down to 60,000 and 29,452 is rounded up to 30,000. 60,000+30,000 is 90,000
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Brianna visits 20 houses every day in her
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6 days

Step-by-step explanation:

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Question 134 (plz help) (ps I luv u)
stiv31 [10]

Answer:

<B = 108 degrees

Step-by-step explanation:

<A = <B  <u><em> (Alternate Angles are congruent)</em></u>

So,

6x+18 = x+93

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4 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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