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AlladinOne [14]
3 years ago
6

The eighth term of an arithmetic sequence is double the value of the third term. The fifth term is equal to 14. Determine the fi

rst term and the common difference of the sequence.
Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer: first term = 6

Common difference = 2

Step-by-step explanation:

Eight term =a +(n-1)d = a +(8-1)d = a + 7d

Third term = a+(n-1)d = a + (3-1)d =a + 2d

a + 7d = 2(a + 2d)

a + 7d = 2a + 4d

7d - 4d = 2a - a

a = 3d

The fifth term is equal to 14. This is:

a + 4d = 14

Put the value of a into the equation here

3d + 4d = 14

7d = 14

d = 14/7

d = 2

Recall that a + 4d = 14

a + 4(2) = 14

a + 8 = 14

a = 14 - 8

a = 6

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Rolling a number less than 4 on a number cube labeled 1 through 6
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3 0
3 years ago
Solve each equation. Record your work and check your solution. <br> a. 5(x-2)+(-9)= -7(1-x)
Daniel [21]

The solution for equation is x = -6

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

5(x-2) + (-9) = -7(1-x)

We have to solve the equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Therefore, solve for brackets in given equation

5(x-2) + (-9) = -7(1-x)\\\\5x - 10 -9 = -7 + 7x

Solve for terms in left hand side of equation

5x - 19 = -7+7x

Move the variables to one side and constants to other side

7x -5x = -19+7\\\\2x = -12\\\\Divide\ both\ sides\ by\ 2\\\\x = -6

Thus the solution for equation is x = -6

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3 years ago
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