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slamgirl [31]
4 years ago
6

Whats the answer please help

Mathematics
1 answer:
geniusboy [140]4 years ago
4 0

Answer: The answer is 68 degrees.

Step-by-step explanation: All angles in a triangle add up to 180 degrees. Since you have 2 of the angles, simply subtract 90 degrees and 22 degrees from 180 to get the last angle. Hope that helped!

You might be interested in
How do you solve the quadratic equation (x-2)^=49
Usimov [2.4K]
Assuming you mean
(x-2)²=49
sqare root both sides and take positive and negative roots
x-2=+/-7
add 2 to both sides
x=2+/-7
x=2+7 and 2-7
x=9 and -5
7 0
3 years ago
What is the value of n?
bogdanovich [222]

Answer:

<h3>B. 85°</h3>

Step-by-step explanation:

Look at the picture.

We know: Angles on one side of a straight line always add to 180°.

Therefore:

\alpha=180^o-142^o=38^o\\\\\beta=180^o-133^o=47^o

We know: the sum of the measures of the angles of the triangle is equal to 180 °.

Therefore:

\gamma+47^o+38^o=180^o

\gamma+85^o=180^o      <em>subtract 85° from both sides</em>

\gamma=95^o


n^o+95^o=180^o\to n^o=180^o-95^o=85^o

8 0
3 years ago
Read 2 more answers
The table shows a function.
enyata [817]

Answer: I need this too.

Step-by-step explanation:


4 0
3 years ago
How do you think a dolphin jumping out of water relates to a quadratic?
Murrr4er [49]
Sawyer and Emily is so cute I love
8 0
3 years ago
PLEASE HELP
valina [46]

Answer:

Step-by-step explanation:

You have 3 unknowns: a, b, and c.  It's our job to find them algebraically.  I'm going to start with the point where x = 0 and y = 7.  You'll see why in a minute.  Filling in the standard form of a quadratic

y=ax^2+bx+c  using (0, 7):

7=a(0)^2+b(0)+c  gives you that c = 7.  We will use that value now when we write the next 2 equations.  Now the point (-2, 19):

19=a(-2)^2+b(-2)+7  and

19=4a-2b+7 so

12 = 4a - 2b

Now for the next point (-1, 12):

12=a(-1)^2+b(-1)+7  and

12=a-b+7  so

5 = a - b

Now we have a system of equations (the 2 bold font equations) that we will solve by elimination:

 12  =  4a  -  2b

  5  =   a   -    b

Multiply the bottom equation by -4 to get a new system:

 12  =  4a  -  2b

-20  = -4a  +  4b

Add those together to get rid of the a terms and end up with

-8 = 2b so

b = -4

Now we can sub in -4 for b to solve for a.  I'm using the second bold type equation to do this:

5 = a - (-4) and

5 = a + 4 so

a = 1 and the equation for the quadratic function is

y=x^2-4x+7

7 0
3 years ago
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