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Katarina [22]
3 years ago
5

Apply the Binomial Theorem to the expression (x^2+1)^2

Mathematics
2 answers:
timurjin [86]3 years ago
8 0

Answer:

x^4 + 2x^2 + 1

Step-by-step explanation:

Using Pascal's Triangle, we end up with the following set of coefficients in a triangular form:

        1

 1      2     1

The coefficients 1, 2 and 1 are used as follows:

1(x^2)^2 + 2(x^2) + 1(1)^2, or

x^4 + 2x^2 + 1

Therefore the given expression (x^2+1)^2 is equivalent to the expanded form x^4 + 2x^2 + 1 .

KiRa [710]3 years ago
6 0

Answer:

Step-by-step explanation:

(x^2 +1)(x^2 +1)

x^4 +x^2+x^2 +1

x^4+2x^2 +1 answer

Hope this helps!

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If I understand the picture correctly, (a) wants you to find the angle K. It first shows us that both J to K, and L to K are equal in length of 11, thus there is no deviation in angle 35 degrees with L (so they both equal each other). Therefore, the angle K will equal 180 degrees subtracted by the sum of J and L, which is 110 degrees.

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3 0
3 years ago
Suppose r(140°, P)(A) = B and (RPD←→∘RPC←→)(A) = B, what is m∠CPD?
NISA [10]

An angle bisector divides an angle into two equal halves.

The measure of angle \angle CPD is 70 degrees

The complete question is an illustrates the concept of angle bisector;

Where:

\angle RPD = 140^o, and line PC bisects \angle RPD

Because line PC bisects \angle RPD, then it means that the measure of RPD is twice the measure of CPD:

So, we have:

\angle RDP = 2 \times \angle CPD

Substitute \angle RPD = 140^o

140^o = 2 \times \angle CPD

Divide both sides by 2

70^o = \angle CPD

Apply symmetric property of equality:

\angle CPD = 70^o

Hence, the measure of angle \angle CPD is 70 degrees

Read more about angle bisectors at:

brainly.com/question/12896755

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