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olasank [31]
3 years ago
13

What is the distance between (2, -4) and (9, -4)?

Mathematics
2 answers:
alexdok [17]3 years ago
8 0

Answer:

7 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (2, - 4) and (x₂, y₂ ) = (9, - 4)

d = \sqrt{9-2)^2+(-4+4)^2}

   = \sqrt{7^2+0^2}

   = \sqrt{49}

  = 7

jeyben [28]3 years ago
4 0
The student will recognize the characteristics of a composite number based on its factors.
True/False
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explanation: I did the the test

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Which equation is y = 9x2 + 9x – 1 rewritten in vertex form?
Anastasy [175]

Answer:

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Step-by-step explanation:

An equation in the vertex form is written as

y = a (x-h) + k

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For an equation in the form ax ^ 2 + bx + c the x coordinate of the vertex is defined as

x = -\frac{b}{2a}

In this case we have the equation y = 9x^2 + 9x - 1.

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Therefore The encuacion excrita in the form of vertice is:

y = a(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

To find the coefficient a we substitute a point that belongs to the function y = 9x^2 + 9x - 1

The point (0, -1) belongs to the function. Thus.

-1 = a(0 + \frac{1}{2}) ^ 2 -\frac{13}{4}

-1 = a(\frac{1}{4}) -\frac{13}{4}\\\\a = \frac{-1 +\frac{13}{4}}{\frac{1}{4}}\\\\a = 9

<em>Then the written function in the form of vertice is</em>

y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

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