Answer:
If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?
Step-by-step explanation:
First of all, when you want to contrast two hypothesis you need a confidence level p% without which the comparison makes no sense.
In this case, you want to refuse the null hypothesis (the average is 5%) with an alternative one (the average is less than 5%).
You propose a new average (3.6%) based on the evidence.
You cannot prove that the average is actually 3.6%, <em>but if you somehow determine that the probability the average is greater than 3.6% is lower than 100% minus your confidence level p% ,then you can refute the null hypothesis and accept the alternative one as new average.
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So, from the possible choices, the one that fits the best is
If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?
C
Because the letters a and b are variables
Answer: x=1 y=3....do you need to show your work?
The number of new ants appearing in Mark's bedroom each day can be found to be 12 ants per day
<h3>How to find the number of ants?</h3>
To find the number of new ants coming into Mark's room every day, you should divide the difference between the number of ants on consecutive days by the difference between the days since Mark moved in.
The difference between the number of ants from day 3 to 5 is:
= 90 - 66
= 24 ants
The difference in the number of days:
= 5 - 3
= 2 days
The number of new ants is therefore:
= 24 / 2
= 12 ants
Find out more on ants at brainly.com/question/13180306
#SPJ1
Answer:
I believe the answer is D
Step-by-step explanation:
