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3 years ago

(THIS IS ASTRONOMY)

Physics

1 answer:

andrew-mc [135]3 years ago

8 0

Answer:

the answer to this question is A globular cluster

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A photon with a frequency of 5.48 × 10^14 hertz is emitted when an electron in a

mezya [45]

Using the Planck's Equation, comes:

$E=hf \\ E=6.63*10^{-34}*5.48*10^{14}*J \\ \boxed {E=36.3324*10^{-20}*J}$

If you notice any mistake in my english, please let me know, because i am not native.

4 0

3 years ago

Can someone help meeeeee... show how to solve it plzzzzzzzz

liubo4ka [24]

<h2>Right answer: 64 units</h2><h2></h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

$F=G\frac{m_{1}m_{2}}{r^2}$

Where:

$F$ is the module of the force exerted between both bodies

$G$ is the universal gravitation constant.

$m_{1}$ and $m_{2}$ are the masses of both bodies.

$r$ is the distance between both bodies

In this case we have a gravitation force $F_{1}=16units$ , given by the formula written at the beginning. Let’s rename the distance $r$ as $d$ :

$F_{1}=G\frac{m_{1}m_{2}}{d^2}$ (1)

And we are asked to find the gravitation force $F_{2}$ with a given distance of $\frac{d}{2}$ :

$F_{2}=G\frac{m_{1}m_{2}}{({\frac{d}{2})}^{2}}$

$F_{2}=G\frac{m_{1}m_{2}}{{\frac{d^{2}}{4}}}$ (2)

The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate $G m_{1}m_{2}$ in both equations:

From (1):

$Gm_{1}m_{2}=F_{1}{d}^{2}$ (3)

From (2):

$Gm_{1}m_{2}=F_{2}\frac{{d}^{2}}{4}$ (4)

If (3)=(4):

$F_{1}{d}^{2}=F_{2}\frac{{d}^{2}}{4}$ (5)

Now we have to find $F_{2}$ :

$F_{2}=F_{1}{d}^{2}\frac{4}{{d}^{2}}$

$F_{2}=4F_{1}$ (6)

If $F_{1}=16 units$ :

$F_{2}=(4)(16 units)$

$F_{2}=64 units$ >>>>This is the new force of attraction

3 0

3 years ago

Which characteristic should a good scientific question have? A) It should lead to a hypothesis that is not testable. B) it shoul

yarga [219]

Answer:

B. IT should have a very broad focus with many variables.

4 0

3 years ago

On her camping trip, Penelope was in charge of collecting firewood. The firewood she found had a mass of 120 g and a volume of 4

zloy xaker [14]

From the formula: density=mass/volume
But first, we have to convert the cm³ to m³ by multiplying the value in cm³ by 10^-6, by so doing we'll have the volume to be 0.48*10^-3cm³.
we will also need to convert the mass which is in g to kg by simply dividing by 1000 so the mass becomes 0.12kg
Now we can solve for the density using the formula I earlier stated which is the mass divided by the volume =0.12/0.48*10^-3 so the density will be 0.25*10^3kgm-3 or 2.5*10^2kgm-3

3 0

3 years ago

Which property of sound waves decreases as the square of the distance from the source increases?

Vitek1552 [10]

Answer:

Intensity

Explanation:

The intensity of a sound wave is equal to the ratio between to the power emitted by the source divided by the area of the spherical surface through which the wave propagates:

$I=\frac{P}{4\pi r^2}$

where

P is the power

$4\pi r^2$ is the area of the spherical surface

r is the distance from the source

As we see from the formula, the intensity is inversely proportional to the square of the distance from the source:

$I\propto \frac{1}{r^2}$

so, intensity is the correct answer.

3 0

3 years ago