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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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dribeiro
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Answer:
5x+4y=85-
Slope = -2.500/2.000 = -1.250
x-intercept = 85/5 = 17
y-intercept = 85/4 = 21.25000
2x+3y=41-
Slope = -1.333/2.000 = -0.667
x-intercept = 41/2 = 20.50000
y-intercept = 41/3 = 13.66667
What????????????
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Your equation is presented in by the following formula of y = mx + b
m = slope, it is the coefficient of X
y = 4/5 X - 3
m = 4/5
