Answer:
<em>The depth of the submarine was 295 feet</em>
Step-by-step explanation:
<u>Function Modeling</u>
The following expression models the depth of a submarine that began at -370 m and ascended at 15 ft/minute:
d = -370 + 15z
Where z is the time in minutes.
We are required to find the depth of the submarine at t=5 minutes. Substituting t=5 into the function model:
d = -370 + 15(5)
d = -370 + 75
d = -295 feet
The depth of the submarine was 295 feet
186000 is the answer in standard notation
Answer:
solution given:
5x+2y=-6
as we know that slope intercept form is
y=mx+c
so
making above equation like that
2y=-5x-6
<u>y=-5/2x-3 is a slope intercept form</u>
Vertex form is given by:
y=a(x-h)^2+k
where the vertex is (h,k)
7. (h,k)=(-4,1)
plugging in the equation we get:
y=a(x+4)^2+1
but substituting (0,2) in the equation and solving for a we get:
2=a(0+4)^2+1
a=1/16
hence:
Answer: y=1/16(x+4)^2+1
8]
(h,k)=(2,-4)
thus
y=a(x-2)^2-4
plugging point (3,0) in the eqn and solving for a we get
0=a(3-2)^2-4
0=a-4
a=4
hence;
Answer: y=a(x-2)^2-4
9] (h,k)=(3,3)
thus;
y=a(x-3)^2+3
plugging (2,2) in the equation we get:
2=a(-1)^2+3
a=-1
thus;
Answer: y=-1(x-3)^2+3
10] (h,k)=(-1,-1)
y=a(x+1)^2-1
plugging (0,-3) in the equation and solving for a we get:
-3=a(1)^2-1
a=-2
thus
Answer: y=-2(x+1)^2-1
11] (h,k)=(1,2)
y=a(x-1)^2+2
plugging (0,4) in the equation and solving for a we get:
4=a(-1)^2+2
a=2
thus
y=2(x-1)^2+2
12] (h,k)=(3,-2)
y=a(x-3)^2-2
plugging (2,0) and solving for a we get:
0=a(2-3)^2-2
a=2
thus
t=2(x-3)^2-2
Answer:
z=4√5
Step-by-step explanation:
use the Pythagorean theorem to set up a system of equations. a^2 + b^2 = c^2
16+4= 20
20^2 = x^2 + z^2 400=x^2 + z^2 x^2=400-z^2
z^2 = 4^2 + y^2 z^2 = 16 + y^2
x^2 = 16^2 + y^2 x^2 = 256 + y^2 y^2=x^2-256
z^2=16+x^2-256
z^2=16+400-z^2-256
z^2=160-z^2
2z^2=160
z^2=80
z= √80 =4√5
