What is the solution of the inequality below? y-1≥0

A circle has been split into 8 sectors each of which can be colored as 4 different colors, and no consecutive sectors are colore

Eva8 [605]

Answer:

5832 ways

Step-by-step explanation:

Since the circle has 8 sectors and there is 4 colour,

Assuming the sectors are numbered 1 to 8,

Sector 1 : can be coloured with any of the 4 colour in 4 ways

Sector 2 can be coloured with any of the remaining 3 colours in 3 ways

Sector 3 in 3 ways without using the colour in sector 2

Sector 4 in 3 ways without using the colour in sector 3

Sector 5 in 3 ways without using the colour in sector 4

Sector 6 in 3 ways without using the colour in sector 5

Sector 7 in 3 ways without using the colour in sector 6

Sector 8 in 2 ways without using the colours in sector 1 and 7

Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways

3 0

3 years ago

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

Hey another one so sorry T^T

konstantin123 [22]

Answer and Step-by-step explanation:

-6 and -10 are the answers.

This is because these numbers are less than -5, so they would work when plugged in for h in the inequality.

#teamtrees #PAW (Plant And Water)

8 0

3 years ago

Read 2 more answers

What is the image of the photo and the preimage?

Anna [14]

Answer:

a shape with 4 sides

Step-by-step explanation:

duh

7 0

3 years ago

The length of one side of a triangular lot is 6 m less than 3 times the length of the second side. The third side is 8 m longer

Tanya [424]

second side = x

first side = 3x - 6

third side = (3x - 6) + 8

The perimeter = 80m and is equal x + (3x - 6) + [(3x - 6) + 8]

x + 3x - 6 + 3x - 6 + 8 = 80

7x - 4 = 80 |+4

7x = 84 |:7

x = 12 m

3x - 6 = 3(12) - 6 = 30 m

(3x - 6) + 8 = 3x + 2 = 3(12) + 2 = 38 m

Answer: 12m, 30m, 38m

8 0

3 years ago