Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So






Rounding up
We need a sample size of 564.
You would use the sine rule. This is because the sine rule is when you know two of the angles on any triangle.
Brainliest please! <3
Answer:
x = 0.5
Step-by-step explanation:
Given
2(x + 1.25) = 3.5 ← divide both sides by 2
x + 1.25 = 1.75 ( subtract 1.25 from both sides )
x = 0.5