Answer:
a) r = 0.974
b) Critical value = 0.602
Step-by-step explanation:
Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below
Test A | 64 48 51 59 60 43 41 42 35 50 45
Test B | 91 68 80 92 91 67 65 67 56 78 71
To find - (a) What is the value of the linear coefficient r ?
(b) Assuming a 0.05 level of significance, what is the critical value ?
Proof -
A)
r = 0.974
B)
Critical Values for the Correlation Coefficient
n alpha = .05 alpha = .01
4 0.95 0.99
5 0.878 0.959
6 0.811 0.917
7 0.754 0.875
8 0.707 0.834
9 0.666 0.798
10 0.632 0.765
11 0.602 0.735
12 0.576 0.708
13 0.553 0.684
14 0.532 0.661
So,
Critical r = 0.602 for n = 11 and alpha = 0.05
|3+10|=|3|+|10|
|13|=|13|
13=13
Answer:
I think the answer is D but I'm not 100 percent sure. I hope this helps
Step-by-step explanation:
I think I took this test before
Answer:
For solving x x= -24+y/4 For solving Y y=−24−4x
Step-by-step explanation:
This is solving for x
Add y to both sides.
−4x=24+y
Divide both sides by -4
and the answer is
x= -24+y/4
THis is solving Y
Add 4x to both sides
−y=24+4x
Multiply both sides by -1
and the answer is
y=−24−4x
Answer:
5
Step-by-step explanation: