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Serjik [45]
2 years ago
5

HELP PLS I GOT 9 MINUTESS

Mathematics
2 answers:
Aloiza [94]2 years ago
8 0

Answer:

84

Step-by-step explanation:

pretty sure

slega [8]2 years ago
5 0
84!!!!!!!!!!!!!!!!shdhdhshhsis
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I need help pleasssss
Yakvenalex [24]

Answer:

  3)  16.2

Step-by-step explanation:

The supplement to the 115° angle on the right is 65°, the same as the angle at upper left. The vertical angles at C are the same measure, so this tells you that the two triangles FCB and ACD are similar by the AA similarity postulate. That being the case, corresponding sides are proportional:

  CB/CD = CF/CA

  CB = CD·CF/CA = 7.2·21.6/9.6

  CB = 16.2

_____

When given two "point-to-point" triangles like this, quite often there is some sort of similarity relationship involved. First, you need to figure out what it is; then you need to make use of it as needed to answer the question being asked.

4 0
3 years ago
Please help everything you need is on the picture.
satela [25.4K]
She would need to buy 75% of the dress Bc 100%-25% is 75%
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2 years ago
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Please help it’s urgent!! Find the sine, cosine and tangent of angle B. Leave answers as reduced fractions.
BigorU [14]

Answer:

sin(B) = 4/5

cos(B) = 3/5

tan (B) = 4/3

Step-by-step explanation:

soh cah toa

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2 years ago
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Which of the following is not an integer?<br><br> 0<br> 0.54<br> -45<br> 17
mart [117]
Decimals are not an integer, so that’s making 0.54 not an integer
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2 years ago
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Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
3 years ago
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